【问题标题】:Adding ajax jQuery File upload添加ajax jQuery文件上传
【发布时间】:2015-11-24 04:57:23
【问题描述】:

所以,我有以下图片上传表格:

HTML:

<form name="upload_image">
    <input id="fileupload"  type="file" name="files[]" class="files rhiu" onchange="UploadImage(event);" accept='image/*'/>
    <div id="progress">
        <div class="bar" style="width: 0%;"></div>
    </div>
    <ul id="fileList">
    <!-- The file list will be shown here -->
    </ul>   
</form>

PHP:

add_action( 'wp_ajax_UploadImage', 'UploadImage' );
add_action( 'wp_ajax_nopriv_UploadImage', 'UploadImage' );
function UploadImage()
{
$upload_dir = wp_upload_dir();
$files = $_FILES['files'];
foreach ($files['name'] as $key => $value) {            
    ...ADDING IMAGE TO A POST...
    } 
} 
echo json_encode($image_path);
exit;
}

JS:

function UploadImage(e)
{
  var form = document.forms.namedItem("upload_image"); 
  var formdata = new FormData(form); 
  formdata.append('action', 'UploadImage');
  jQuery.ajax({
    type: "POST",
    dataType: "json",
    url: upload_image.ajax_url, 
    data: formdata,
    contentType: false,
    processData: false,
    success: function(data) {                   
      alert('Success');
    }       
  });
}

至此,一切正常。

但我正在尝试按照选择的答案here 将 Bluimp jQuery 文件上传作为上传处理程序。

我很难使用ajax option

这就是我想要做的:

  1. 使用blueimp jQuery文件上传上传图片。
  2. 通过 ajax 函数(“UploadImage”)添加数据。

我需要在 js 中进行哪些更改才能包含插件?

我尝试了什么:

var form = document.forms.namedItem("upload_video"); 
var formdata = new FormData(form); 
formdata.append('action', 'UploadImage');
$('#fileupload').fileupload({
  type: "POST",
  dataType: "json",
  url: upload_image.ajax_url, 
  data: formdata,
  add: function (e, data) {
    var tpl = $('<li class="working">'+
      '<input type="text" value="0" data-width="48" data-height="48" data-fgColor="#0788a5" data-readOnly="1" data-bgColor="#3e4043" />'+
        '<p></p><span></span></li>' );
    tpl.find('p')
      .text(data.files[0].name)
      .append('<i>' + formatFileSize(data.files[0].size) + '</i>');
    data.context = tpl.appendTo(ul);
    tpl.find('span')
      .click(function() {
        if (tpl.hasClass('working')) {
          jqXHR.abort();
        }
        tpl.fadeOut(function(){
          tpl.remove();
        });
      });
    var jqXHR = data.submit();
  },
  progressall: function (e, data) {
    var progress = parseInt(data.loaded / data.total * 100, 10);
    $('#progress .bar').css(
        'width',
        progress + '%'
    );
  }
});

【问题讨论】:

    标签: javascript php jquery ajax


    【解决方案1】:

    我注意到的第一件事是 HTML

    Need to make form multi-part for image uploading
    

    【讨论】:

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