将多个值插入数据库，php，sql

Question

我在尝试将多个值同时插入表的同一列时遇到问题，

这段代码显示了一个表格： 表例：

-----------------------------
Name   | Last Name | Points |
-----------------------------
Test   | 185       |        |
-----------------------------
Test1  | 185       |        |
-----------------------------
Test2  | 185       |        |
-----------------------------

useradmin 可以为每个用户插入点，但是当我单击 summint 将所有这些值插入数据库时​​，我会收到一条消息（错误） PDO::prepare() 期望参数 1 是字符串，数组在 还有一个 致命错误：在非对象上调用成员函数 execute()

任何想法为什么或如何修复？

<?php
require("coneccion.php"); 

if(!empty($_POST))
{ 

  $query = "INSERT INTO points (sid, ais, spoints) values (1, 2, :spoints)";
  $query = array(':spoints' => $_POST['spoints']);

  try
  {
    $stmt = $db->prepare($query);
    $stmt = $stmt->execute($query_params);
  }
  catch(PDOException $ex)
  {
    die("Error 1 " . $ex->getMessage());
  }
  $cid = $_SESSION['cid'];
  header("Location: index.php?id=$cid");
  die("Rendirecting to index.php?id=$cid");
}
else
{

  $id = $_SESSION['cid'];
  echo 'Course id: ' .$id ;
  $sid = $_GET['id'];

  $query = "SELECT DISTINCT s.studentid, s.fname, s.lname, a.assignmentpoints, s.courseid, a.courseid, a.duedate FROM students as s, assignments as a WHERE s.courseid = '$id' and s.courseid = a.courseid and a.assignmentid = '$sid' ";
  try
  {
    $stmt = $db->prepare($query);
    $stmt->execute();
  }
  catch(PDOException $ex)
  {
    die("Error 2" . $ex->getMessage());
  }
  $rowstudents = $stmt->fetchAll();
}
?>


<form action="index.php" method="post">
<table border=1>
  <tr>
    <th>Id</th>
    <th>First Name</th>
    <th>Last Name</th>
    <th>Assignment Points</th> 
    <th>Student Points</th>
  </tr>
<?php foreach($rowstudents as $row): ?>
  <tr>
    <th><?php echo '' . htmlentities($row['studentid'], ENT_QUOTES, 'UTF-8') . '';?></th>
    <th><?php echo '' . htmlentities($row['fname'], ENT_QUOTES, 'UTF-8') . '';?></th>
    <th><?php echo '' . htmlentities($row['lname'], ENT_QUOTES, 'UTF-8') . '';?></th>
    <th><?php echo '' . htmlentities($row['assignmentpoints'], ENT_QUOTES, 'UTF-8') . '';?></th> 
    <th><input type="text" name="spoints" value=""></th>
  </tr>
<?php endforeach; ?>
</table>
<input type="submit" value="Submit">
</form>

Answer 1

你在这里重新分配$query：

$query = "INSERT INTO points (sid, ais, spoints) values (1, 2, :spoints)";
$query = array(':spoints' => $_POST['spoints']);

所以，在第二行之后，$query 变成了一个包含一个元素的数组。

我认为你的本意是：

$query = "INSERT INTO points (sid, ais, spoints) values (1, 2, :spoints)";

try
  {
    $stmt = $db->prepare($query);
    $stmt->bindParam(':spoints', $_POST['spoints']);
    $stmt->execute();
  }

参考：http://us3.php.net/pdo.prepared-statements

另外，要获得多个点，请将您的 html 元素更改为：

<input type="text" name="spoints" value="">

到

<input type="text" name="spoints[]" value="">

注意带有数组spoints[] 的名称。发布后，$_POST['spoints'] 将是一个数组，您可以循环并添加记录。

$points = null;

$query = "INSERT INTO points (sid, ais, spoints) values (1, 2, :spoints)";

try
{
    $stmt = $db->prepare($query);
    $stmt->bindParam(':spoints', $points);
    foreach($_POST['spoints'] as $value) {
        $points = $value;
        $stmt->execute();
    }
}
catch(PDOException $ex)
{
    die("Error 1 " . $ex->getMessage());
}