Laravel：让用户选择模型然后获取查询

Question

我正在做一个 Laravel 项目，它应该有点模块化。

我写了一个搜索查询，我想要的如下：

型号：
评估A
评估B
评估C

查看：

{{ Form::open(array('route' => 'search')) }}

<select multiple name="search_by_form[]">
 <option selected>Any</option>
 <option value="assessment_a">A</option>
 <option value="assessment_b">B</option>
 <option value="assessment_c">C</option>
               
</select>
{{ Form::close() }}

控制器：
控制器要复杂得多，但我让您更容易理解我的需求。
现在如下所示：

$user_entry =$request->input('search_by_form', []);
$resultArray = [];
foreach ($user_entry as $entry){
  if ($entry == "assessment_a"){
      $model_results = AssessmentA::where("approved",1)->get();
  
  } elseif ($entry == "assessment_b"){
      $model_results = AssessmentB::where("approved",1)->get();
  } elseif($entry == "assessment_c"){
      $model_results = AssessmentC::where("approved",1)->get();
  }
}

我想要什么：

搜索视图控制器： 遍历特定文件夹中的模型

然后：

{{ Form::open(array('route' => 'search')) }}

<select multiple name="search_by_form[]">
  
 <option selected>Any</option> 
 @foreach($models as $model)
 <option value="{{ $model }}">{{ $model->name }}</option>
  @endforeach
</select>
{{ Form::close() }}

除了采用这种丑陋的方法之外，是否可以采用更多类似的方法：

foreach ($user_entry as $entry){

   $entry::where("approved",1)->get(); #Obviously the values on the view would be change to "AssessmentA", etc.

}

这可行吗？

提前致谢！

Answer 1

我想你会创建任何这样的数组：

$model_array = ['assessment_a' => AssessmentA::class];

然后在循环中简单地传递值

foreach ($user_entry as $entry){

   $model_array[$entry]::where("approved",1)->get(); #Obviously the values on the view would be change to "AssessmentA", etc.

}

Answer 2

如果您将选择值更改为实际的表名，您可以轻松完成

{{ Form::open(array('route' => 'search')) }}
<select multiple name="search_by_form[]">
 <option selected>Any</option>
 <option value="assessments_a">A</option>
 <option value="assessments_b">B</option>
 <option value="assessments_c">C</option>
</select>
{{ Form::close() }}

$user_entry = $request->input('search_by_form', []);

if (empty($user_entry)) {
    model_results = collect();
} else {
    $query = DB::table(array_shift($user_entry))->where('approved', 1);

    foreach ($user_entry as $table) {
        $query->union(fn($union) => $union->from($table)->where('approved', 1));
    }

    $model_results = $query->get();    
}