【发布时间】：2018-02-20 05:35:03
【问题描述】：
我正在使用 MySQL 构建一个 MVC PHP Web 应用程序。我正在使用表单从用户那里收集信息。当日期信息以正确的顺序输入时，日期输入起作用，但我希望这对我不太懂技术的同事（上帝保佑他们）更加用户友好。
这是我在 'index.php' 中的表单：
if($action == 'add_order'){
$distributor_id = filter_input(INPUT_POST, 'distributor_id', FILTER_VALIDATE_INT);
$code = filter_input(INPUT_POST, 'code');
$name = filter_input(INPUT_POST, 'name');
$date = filter_input(INPUT_POST, 'date');
if($distributor_id == NULL || $distributor_id == FALSE || $code == NULL ||
$name == NULL || $date ==NULL){
$error = "Invalid order data: Something is wrong";
include('../errors/error.php');
}else{
add_order($distributor_id, $code, $name, $date);
header("Location: .?distributor_id=$distributor_id");
}
}
?>
这是我在 'order_add.php' 中的表单：
<h1>Add order</h1>
<form action="index.php" method="post" id="add_order_form">
<input type="hidden" name="action" value="add_order">
<label>distributor:</label>
<select name="distributor_id">
<?php foreach ($distributors as $distributor) : ?>
<option value="<?php echo $distributor['distributorID']; ?>">
<?php echo $distributor['distributorName']; ?>
</option>
<?php endforeach; ?>
</select>
<br>
<label>Order Code:</label>
<input type="text" name="code">
<br>
<label>Customer Name:</label>
<input type="text" name="name">
<br>
<label>Order Date:</label>
<input type="text" id="date" name="date">
<br>
<label> </label>
<input type="submit" value="Add order">
<br>
</form>
<p class="last_paragraph">
<a href="index.php?action=list_orders">View order List</a>
</p>
</main>
这里是视图'header_two_date_picker.php'：
<!DOCTYPE html>
<!-- This header page is going to be used with my Order Schedule PHP Program and main_two.css-->
<html>
<!-- This is the body section-->
<head>
<title>Order Status</title>
<link rel='stylesheet' type='text/css' href = "../main_two.css">
<meta charset="utf-8">
<meta name="viewport" content="width=device-width, initial-scale=1">
<title>jQuery UI Datepicker - Default functionality</title>
<link rel="stylesheet" href="//code.jquery.com/ui/1.12.1/themes/base/jquery-ui.css">
<link rel="stylesheet" href="/resources/demos/style.css">
<script src="https://code.jquery.com/jquery-1.12.4.js"></script>
<script src="https://code.jquery.com/ui/1.12.1/jquery-ui.js"></script>
<script>
$( function(){
$( "#date" ).datepicker();
} );
</script>
</head>
<!-- This is the body section-->
<body>
<header>
<h1>My PHP Sandbox - Date Picker</h1>
</header>
这是我的模型“order_db.php”
function add_order($distributor_id, $code, $name, $date){
global $db;
$query = 'INSERT INTO orders
(distributorID, orderCode, orderName, orderDate)
VALUES
(:distributor_id, :code, :name, :date)';
$statement = $db->prepare($query);
$statement->bindValue(':distributor_id', $distributor_id);
$statement->bindValue(':code', $code);
$statement->bindValue(':name', $name);
$statement->bindValue(':date', $date);
$statement->execute();
$statement->closeCursor();
}
?>
jQuery DatePicker 显示甚至填充表单字段，但我的数据库中的表显示“0000-00-00”。
我的问题是：如何获取 DatePicker 数据，并将其转换为 MySql 将存储的日期格式？
感谢您抽出宝贵时间查看我的问题。
这是我的“order_list.php”文件的一部分
<!-- Display table of orders -->
<h2><?php echo $distributor_name; ?></h2>
<table>
<tr>
<th>Order Code</th>
<th>Order Name</th>
<th>Order Date</th>
<th> </th>
</tr>
<?php foreach ($orders as $order) : ?>
<tr>
<td><?php echo $order['orderCode']; ?></td>
<td><?php echo $order['orderName'] ?></td>
<td><?php echo $order['orderDate'] ?></td>
<td><form action="." method="post">
<input type="hidden" name="action" value="delete_order">
<input type="hidden" name="order_id" value="<?php echo $order['orderID']; ?>">
<input type="hidden" name="distributor_id" value="<?php echo $order['distributorID']; ?>">
<input type="submit" value="Delete">
</form></td>
</tr>
<?php endforeach; ?>
</table>
<p class = "last_paragraph">
<a href="?action=show_add_form">Add order</a>
</p>
***<h2>This is a test to output $date: <?php echo $date; ?></h2>
<h2>This is a test to output echo $_POST['date']: <?php echo*** $_POST['date']; ?></h2>
【问题讨论】：
-
您是否尝试过打印以筛选您在数据库中插入的值？也许
$date变量没有你认为的那样。
标签： php jquery mysql model-view-controller datepicker