如何在Javascript中的字符串中的单词之间添加逗号

Question

我正在尝试在括号中的名字和姓氏之间添加逗号。

//Input:

s = "Fred:Corwill;Wilfred:Corwill;Barney:Tornbull;Betty:Tornbull;Bjon:Tornbull;Raphael:Corwill;Alfred:Corwill";

//Expected output: "(CORWILL, ALFRED)(CORWILL, FRED)(CORWILL, RAPHAEL)(CORWILL, WILFRED)(TORNBULL, BARNEY)(TORNBULL, BETTY)(TORNBULL, BJON)"

我的代码当前输出的是什么：

(CORWILL ALFRED) (CORWILL FRED) (CORWILL RAPHAEL) (CORWILL WILFRED) (TORNBULL BARNEY) (TORNBULL BETTY) (TORNBULL BJON)

我尝试了多种方法，例如在重新分配 s（字符串）时更改字符在开头的替换方式，这样我就不会首先删除逗号，然后必须替换它们.. .但是当我这样做时，我拥有的正则表达式不再工作，我不知道为什么会这样。所以我试图找到另一个正则表达式来使用，这样我就可以解决这个问题，但这同样是一个痛苦，所以我决定坚持以这种方式解决它：试图找到一种在第一个之间找到逗号的方法，和括号中的姓氏。

完整问题和代码：

/*Could you make a program that 
    •   makes this string uppercase
    •   gives it sorted in alphabetical order by last name. 
When the last names are the same, sort them by first name. Last name and first name of a guest come in the result between parentheses separated by a comma.
*/

function meeting(s) {

  s = s.replace(/:/g, ", ").toUpperCase();

  //order alphabetically based on Last, then first name
 const semicolon = ';'
 let testArr = s.split(semicolon)
  testArr.sort(function compare(a, b) {
      var splitA = a.split(",");
      var splitB = b.split(",");
      var firstA = splitA[0]
      var firstB = splitB[0]
      var lastA = splitA[splitA.length - 1];
      var lastB = splitB[splitB.length - 1];

      if (lastA < lastB) return -1;
      if (lastA > lastB) return 1; 

      if (firstA < firstB) return -1; //sort first names alphabetically
      if (firstA > firstB) return 1; 
      return 0; //if they are equal
  })
  //print last names before first names with regex
let newArr = [];
for (let i = 0; i < testArr.length; i++) {
  let variable = (testArr[i].replace(/([\w ]+), ([\w ]+)/g, "$2 $1"))
  let comma = ","
  newArr.push(`(${variable})`)
  }
  
let finalStr;
finalStr = newArr.toString().replace(/[ ,.]/g, " ").toUpperCase();
// finalStr = finalStr.replace(/" "/g, ", ")
return finalStr
}

s = "Fred:Corwill;Wilfred:Corwill;Barney:Tornbull;Betty:Tornbull;Bjon:Tornbull;Raphael:Corwill;Alfred:Corwill";

console.log(meeting(s))

// expected result: "(CORWILL, ALFRED)(CORWILL, FRED)(CORWILL, RAPHAEL)(CORWILL, WILFRED)(TORNBULL, BARNEY)(TORNBULL, BETTY)(TORNBULL, BJON)"

任何帮助将不胜感激，我在这个问题上花了大约 5 个小时。我使用的正则表达式是用名字的位置（Fred Corwill）->（Corwill Fred）切换姓氏的位置。如果有一个 regex 对我来说不是你可以建议的我正在使用的那个，也许我也可以通过这种方式解决这个问题，到目前为止我所尝试的一切都没有工作我在这里使用的一个。

Answer 1

这看起来比实际需要的要复杂得多。通过;s 拆分后，将每个单独的元素以相反的顺序映射到其单词，然后加入：

const s = "Fred:Corwill;Wilfred:Corwill;Barney:Tornbull;Betty:Tornbull;Bjon:Tornbull;Raphael:Corwill;Alfred:Corwill";

const output = s
  .toUpperCase()
  .split(';')
  .sort((a, b) => {
    const [aFirst, aLast] = a.split(':');
    const [bFirst, bLast] = b.split(':');
    return aLast.localeCompare(bLast) ||  aFirst.localeCompare(bFirst);
  })
  .map((name) => {
    const [first, last] = name.split(':');
    return `(${last}, ${first})`;
  })
  .join('');
console.log(output);

Answer 2

这就是你需要的：

const str = 'Fred:Corwill;Wilfred:Corwill;Barney:Tornbull;Betty:Tornbull;Bjon:Tornbull;Raphael:Corwill;Alfred:Corwill';

function formatString(string) {
  const modifiedString = string.toUpperCase().replace(/(\w+):(\w+)/g, '($2, $1)');
  const sortedString = modifiedString.split(';').sort().join('');
  
  return sortedString;
}

console.log(formatString(str))

Answer 3

在地图和排序中使用拆分

var s = "Fred:Corwill;Wilfred:Corwill;Barney:Tornbull;Betty:Tornbull;Bjon:Tornbull;Raphael:Corwill;Alfred:Corwill";

var res = s.split(/;/) // split into people
  .map(x => x.split(/:/).reverse()) // split names, put last first
  .sort((a, b) => a[0] === b[0] ? a[1].localeCompare(b[1]) : a[0].localeCompare(b[0])) // sort by last name, first name
  .map(x => `(${x.join(', ')})`) // create the new format
  .join(' ') // join the array back into a string
console.log(res);