使用codeigniter和mysql在单个表中显示付款和收据记录

Question

型号：

$this->db->where('payment_details.created_on >= ',$start_date);
    $this->db->where('payment_details.created_on <= ',$end_date);
    $this->db->where('receipt_details.created_on >= ',$start_date);
    $this->db->where('receipt_details.created_on <= ',$end_date);        
    $this->db->select('payment_details.id,payment_details.payment_no,payment_details.site_id,payment_details.vendor_id,payment_details.work,payment_details.description,payment_details.date,payment_details.amount,payment_details.tax_type,payment_details.tax,payment_details.subtotal,payment_details.grand_total,payment_details.created_on,receipt_details.id,receipt_details.receipt_no,receipt_details.site_id,receipt_details.vendor_id,receipt_details.work,receipt_details.description,receipt_details.date,receipt_details.amount,receipt_details.tax_type,receipt_details.tax,receipt_details.subtotal,receipt_details.grand_total,receipt_details.created_on,vendor.id,vendor.vname,site.id,site.sname');

$this->db->from('payment_details');        
$this->db->join('vendor','vendor.id=payment_details.vendor_id OR vendor.id=receipt_details.vendor_id','LEFT');
$this->db->join('site','site.id=payment_details.site_id OR site.id=receipt_details.site_id','LEFT');
return $this->db->get()->result();

enter image description here

我会尝试，但运行此查询时出现错误 错误： 错误号：1064

您的 SQL 语法有错误；检查与您的 MariaDB 服务器版本相对应的手册，以在第 2 行的 'LEFT JOIN vendor ON vendor.id=payment_details.vendor_id OR vendor.`i' 附近使用正确的语法

选择payment_details.id, payment_details.payment_no, payment_details.site_id, payment_details.vendor_id, payment_details.@9876544330@.payment_details.payment_details @,payment_details.date,payment_details.amount,payment_details.tax_type,payment_details.tax,payment_details.payment_details,payment_details,@987654352. payment_details.created_on, receipt_details.id, receipt_details.receipt_no, receipt_details.site_id, receipt_details.vendor_id, receipt_details.work, @987654366 @.description, receipt_details.date, receipt_details.amount, receipt_details.tax_type, receipt_details.tax, @987654377., @9876454376@, @9876 grand_total，receipt_details。created_on，@vendor。id，vendor。987654384@.。 987654391@.id=payment_details.vendor_id OR vendor.id=receipt_details.vendor_id LEFT JOIN site ON site.id=payment_details.@987654403 @ 或 site.id=receipt_details.@9876 54407@ WHERE payment_details.created_on >= '2018-05-01' AND payment_details.created_on receipt_details.created_on >= '2018-05 -01' AND receipt_details.created_on

文件名：D:/xampp/htdocs/construct/system/database/DB_driver.php

行号：691 提前谢谢......

Answer 1

希望对您有所帮助：（未测试）

你的查询结构应该是这样的，做必要的改变给你提示

$sql = 'SELECT payment_details.id,payment_details.payment_no,payment_details.site_id,payment_details.vendor_id,payment_details.work,payment_details.description,payment_details.date,payment_details.amount,payment_details.tax_type,payment_details.tax,payment_details.subtotal,payment_details.grand_total,payment_details.created_on,receipt_details.id,receipt_details.receipt_no,receipt_details.site_id,receipt_details.vendor_id,receipt_details.work,receipt_details.description,receipt_details.date,receipt_details.amount,receipt_details.tax_type,receipt_details.tax,receipt_details.subtotal,receipt_details.grand_total,receipt_details.created_on,vendor.id,vendor.vname,site.id,site.sname 
        FROM payment_details  
        JOIN (vendor, receipt_details, site)
        ON (vendor.id=payment_details.vendor_id OR vendor.id=receipt_details.vendor_id
        AND site.id=payment_details.site_id OR site.id=receipt_details.site_id)';
$query = $this->db->query($sql);
return $query->result();