用于 Json 输出的 php 数组答案

【问题标题】：Array with php for Json output用于 Json 输出的 php 数组
【发布时间】：2013-02-12 11:13:32
【问题描述】：

我正在尝试获得最佳实践来操作我的数组以获取类似于此格式的 json（更好地使用图表）

   {
    "serieMonth":["Aug-12","Sep-12","Oct-12","Nov-12","Dec-12","Jan-13","Feb-13"],
    "serieCA":[4214,10119,13325,12818,7177,20628,7664],
    "serieAdwordsCA":[0,0,0,0,0,310,332],
    "serieBooking":[10,28,46,34,17,51,16],
    "serieAdwords":[0,0,0,0,0,1,1],
    "serieTotalBooking":[10,28,46,34,17,52,17],
    "serieCartRepartition":[421,361,290,377,422,397,451],
    "serieTotalCart":[421,361,290,377,422,397,451]
    }

其实我的输出是这样的：

[
{"date_year":"2012","date_month":"08","ad_cost":"0.0","ad_clicks":"0"},
{"date_year":"2012","date_month":"09","ad_cost":"0.0","ad_clicks":"0"},
{"date_year":"2012","date_month":"10","ad_cost":"0.0","ad_clicks":"0"},
{"date_year":"2012","date_month":"11","ad_cost":"0.0","ad_clicks":"0"},
{"date_year":"2012","date_month":"12","ad_cost":"44.9","ad_clicks":"43"},
{"date_year":"2013","date_month":"01","ad_cost":"297.56","ad_clicks":"462"},
{"date_year":"2013","date_month":"02","ad_cost":"82.5","ad_clicks":"103"}
]

我正在使用 javascript 来更改它：

var xAxisLabels = new Array(),
adClicks = new Array(),
adCost = new Array();
$.each(data, function(i,v) {
  xAxisLabels.push(v["date_month"]+'/'+v["date_year"]);
  adCost.push(parseInt(v["ad_cost"]));
  adClicks.push(parseInt(v["ad_clicks"]));
});

我正在寻找在 php 中执行此操作的最佳方法，因为我通过 google api 获取这些数据，这是我的 php。

// dimensions
$dimensions = 'ga:year,ga:month';
$_params[] = 'date_year';
$_params[] = 'date_month';
// metrics
$metrics = 'ga:adCost,ga:adClicks';
$_params[] = 'ad_cost';
$_params[] = 'ad_clicks';

$response = $service->data_ga->get('ga:' . $projectId, $from, $to, $metrics, array('dimensions' => $dimensions));

$analyticsStats = array();
foreach ($response['rows'] as $row) {
  $dataRow = array();
  foreach ($_params as $colNr => $column) {
    $dataRow[$column] = $row[$colNr];
  }
  array_push($analyticsStats, $dataRow);
}

【问题讨论】：

“输出”似乎不包含构建“输入”所需的所有值。
是的，输出是我想要得到的格式的一个例子。

标签： php javascript arrays json google-analytics

【解决方案1】：

您可以构建一个数组数组，然后在循环中向子数组添加项：

$output = array(
    "serieMonth" => array(),
    "serieCA" => array(),
    "serieAdwordsCA" => array(),
    "serieBooking" => array(),
    "serieAdwords" => array(),
    "serieTotalBooking" => array(),
    "serieCartRepartition" => array(),
    "serieTotalCart" => array()
);
foreach($response["rows"] as $row) {
    $output["serieMonth"][] = date("Y-M", strtotime("{$row['date_year']}-{$row['date_month']}-01"));
    $output["serieCA"][] = $row["ad_cost"];
    $output["serieAdwordsCA"][] = $row["ad_clicks"];
    // etc...
}
echo json_encode($output);

【讨论】：