【发布时间】:2016-08-23 09:41:38
【问题描述】:
我有一个自动生成选择 html 标记并级联 3 个下拉列表的 JS。现在,我正在尝试使用 json_encode 通过 Mysql 数据库填充下拉列表的数据,但我没有运气。
如何将json_encode从PHP正确解析为JS以使用Mysql自动填充下拉列表?
请帮帮我。
PHP:
$result_region = $wpdb->get_results('SELECT DISTINCT state, city, avenue FROM tablename', OBJECT);
foreach($output as $rows){
$data[] = array('state'=> $rows->state, 'city' => $rows->city,'avenue'=> $rows->avenue);
}
echo json_encode($data);
手动编码数据的工作示例JS:
var data = getData();
var container = document.querySelector("#sl_form");
// initialize select-boxes with data
initSelect(data);
// reads the data and creates the DOM elements (select-boxes and their relevant options)
function initSelect(data) {
var p, select, option, input, filteredOptions;
for (var key in data) {
p = document.createElement("p");
p.innerHTML = key;
select = document.createElement("select");
select.name = key;
container.appendChild(p);
container.appendChild(select);
filteredOptions = optionFilter(data[key].availableOptions, data[data[key].parent], data[key]);
input = document.querySelector('select[name="' + key + '"');
input.setAttribute("onchange", "updateSelect(this)");
for (var i = 0; i < filteredOptions.length; i++) {
option = document.createElement("option");
option.value = filteredOptions[i].value;
option.innerHTML = filteredOptions[i].value;
input.appendChild(option);
}
input.options.selectedIndex = getSelectedIndex(filteredOptions, data[key]);
input.setAttribute('model', data[key].selectedOption.value);
}
}
// this function will be called on change of select-box
function updateSelect(element) {
var input, option;
setSelectedOption(element);
for (var key in data) {
filteredOptions = optionFilter(data[key].availableOptions, data[data[key].parent], data[key]);
input = document.querySelector('select[name="' + key + '"');
while (input.firstChild) {
input.removeChild(input.firstChild);
}
for (var i = 0; i < filteredOptions.length; i++) {
option = document.createElement("option");
option.value = filteredOptions[i].value;
option.innerHTML = filteredOptions[i].value;
input.appendChild(option);
}
input.options.selectedIndex = getSelectedIndex(filteredOptions, data[key]);
input.setAttribute('model', data[key].selectedOption.value);
}
}
// set the selected-option of select-box when it's changed
function setSelectedOption(element) {
var inputName = element.getAttribute("name");
var inputValue = getSelectedText(element);
var inputItem = data[inputName];
var selectedOption, filteredOptions;
// setting selected option of changed select-box
for (var i = 0; i < inputItem.availableOptions.length; i++) {
if (inputValue === inputItem.availableOptions[i].value) {
inputItem.selectedOption = inputItem.availableOptions[i];
break;
}
}
// setting child object selected option now
for (var key in data) {
if (data[key].parent === inputName) {
filteredOptions = optionFilter(data[key].availableOptions, data[data[key].parent], data[key]);
data[key].selectedOption = filteredOptions[0];
}
}
}
// get the text of select-box
function getSelectedText(element) {
if (element.selectedIndex == -1) {
return null;
}
return element.options[element.selectedIndex].text;
}
function getSelectedIndex(options, self) {
var index;
for (var i = 0; i < options.length; i++) {
if (self.selectedOption.value === options[i].value) {
index = i;
break;
}
}
return index;
}
// get filtered options based on parent's selected value
function optionFilter(items, parent, self) {
var result = [];
if (typeof parent !== "undefined") {
for (var i = 0; i < items.length; i++) {
if (typeof parent.selectedOption !== "undefined") {
if (parent.selectedOption !== null && items[i].parentValue === parent.selectedOption.value) {
result.push(items[i]);
}
}
}
if (typeof self.selectedOption === "undefined") {
self.selectedOption = null;
}
if (self.selectedOption === null) {
self.selectedOption = result[0];
}
return result;
} else {
return items;
}
}
【问题讨论】:
-
你不能一个接一个地回显多个 json_encodes,那样会产生无效的 json。将要编码的完整数组放在一起,然后编码一次。
-
您的 JSFiddle 不起作用
-
@scottevans93 现在可以使用了
-
You
<select>在 Fiddle 上仍然是空的。 -
不,不是。请再次点击链接。
标签: javascript php mysql arrays json