使用php将相似数据插入两个表中

Question

我有以下代码用于将表单数据插入到我的数据库中的单个表中。`

function insert_interests($uid, $interests) {
/* first, we'll delete any entries this user already has in the table */
    purge_lookup("jss_users_interests_table", $uid);
/* now create the sql insert query */
    global $db;
    $db->query(create_checkbox_query($interests, "jss_users_interests_table", $uid));
}
/* helper function for insert_interests(). removes all rows in $table with $uid */
function purge_lookup($table, $uid) {
    global $db;
    $db->query("DELETE FROM $table WHERE users_id = '".$db->escape($uid)."'");
}
/* helper function for insert_interests(). generates the actual SQL query */
function create_checkbox_query($arr, $table, $uid) {
    $q = "INSERT INTO $table (users_id, subcategories_id) VALUES";
    foreach ($arr as $check) {
    $q .=  " ( '$uid' , $check )" . ",";
    }
/* remove the last comma and return */  
return substr($q, 0, -1);
}`

在此代码之后，我想使用相同的表单数据与另一个表中的其他数据配对，将新记录插入到另一个表中。这是两个表的结构。

jss_users_interests_table

• users_id
• subcategories_id

jss_info_requests_table

• users_id
• provider_id
• subcategories_id

jss_providers_assignments_table

• provider_id
• subcategories_id

因此，在将数据插入jss_users_interests_table 之后，我需要做的是将相同的数据以及每个subcategories_id's 对应的provider_id 从 jss_provider_assignment_table 插入到 jss_info_requests_table。说得通？我是不是把它搞砸了，让它变得复杂？

任何有关语法的帮助都会很棒。谢谢！

Answer 1

这个 SQL 可能会起作用。

 INSERT INTO jss_info_requests_table 
 (users_id, provider_id, subcategories_id)
SELECT a.users_id,
 b.provider_id, b.subcategories_id FROM
 jss_users_interests_table a,
 jss_providers_assignments_table b 
 WHERE a.subcategories_id =
 b.subcategories_id AND a.users_id =
 [USERID]