【发布时间】:2019-08-22 07:51:29
【问题描述】:
我的代码有错误:
where 子句中的列 'id_member' 不明确
A Database Error Occurred
Error Number: 1052
Column 'id_member' in where clause is ambiguous
SELECT *, `aa`.`id_member` FROM `tb_permohonan` `aa` LEFT JOIN `tb_member` `bb` ON `aa`.`id_member`=`bb`.`id_member` LEFT JOIN `tb_jenis_uttp` `cc` ON `aa`.`id_jenis_uttp` =`cc`.`id_jenis_uttp` WHERE `id_member` = '1'
Filename: C:/xampp/htdocs/web/system/database/DB_driver.php
Line Number: 691
这是我的控制器:
public function v_print_surat()
{
$start = intval($this->input->get('start'));
$id = $this->session->userdata('id_member');
$data_where = array('id_member', $id);
$print = $this->Tb_permohonan_model->get_by_where($data_where);
if ($print) {
$data = array(
'print' => $print,
'start' => $start,
'content' => "frontend/v_print_surat",
);
$this->load->view('layout/frontend', $data);
} else {
$this->session->set_flashdata('message', 'Record Not Found');
redirect(site_url('frontend'));
}
}
这是我的模特:
function get_by_where($data)
{
$this->db->select("*, aa.id_member");
$this->db->where($data[0], $data[1]);
$this->db->join('tb_member bb','aa.id_member=bb.id_member','left');
$this->db->join('tb_jenis_uttp cc','aa.id_jenis_uttp =cc.id_jenis_uttp','left');
return $this->db->get($this->table." aa")->result();
}
谁能帮忙?
【问题讨论】:
标签: php codeigniter codeigniter-3