使用 PDO 构造 http_build_query 并选择

Question

我正在尝试创建一个 http_build_query 数组，但它插入了一些不同的字符，这是我的代码：

function Conectar(){
    try{
        $opcoes = array(PDO::MYSQL_ATTR_INIT_COMMAND => 'SET NAMES UTF8');
        $con = new PDO("mysql:host=localhost; dbname=*****;", "*****", "*****", $opcoes);
        $con->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);

        return $con;
    } catch (Exception $e){
        echo 'Erro: '.$e->getMessage();
        return null;
    }
}

$pdo = Conectar();

    $sql = "
    SELECT dominio 
    FROM dominios_extraidos 
    WHERE verificado='0' LIMIT 3
    ";

    $stm = $pdo->prepare($sql);
    $stm->execute();

while ($rows = $stm->fetch()) {
    $query = http_build_query(array(
        'domains' => array(
            ''.$rows['dominio'].'',
        )
    ));
    
    
    print_r($query);
    }

创建此输出：

domains%5B0%5D=0002021web.com.br%0Adomains%5B0%5D=007import.com.br%0Adomains%5B0%5D=00pet.com.br%0A

但这是我想要的输出：

domains%5B0%5D=0002021web.com.br&domains%5B1%5D=007import.com.br&domains%5B2%5D=00pet.com.br

可以使用此代码手动生成我想要的输出：

$query = http_build_query(array(
        'domains' => array(
            '0002021web.com.br',
            '007import.com.br',
            '00pet.com.br',
        )
    ));
    
    
    print_r($query);

感谢您的宝贵时间:)

Answer 1

您想先正确构建数组，使其看起来像您的手动数组，然后使用 http_build_query：

$domains = ['domains' => []];
while ($rows = $stm->fetch()) {
    $domains['domains'][] = trim($rows['dominio']);
}

$query = http_build_query($domains);
print_r($query);

Answer 2

在循环中创建一个域数组，然后在循环完成后将其作为参数传递给http_build_query()。

while ($rows = $stm->fetch()) {
    $doms[] = trim($rows['dominio']);
}

$query = http_build_query( ['domains' => $doms] );
    
print_r($query);

这会产生

domains%5B0%5D=0002021web.com.br%0A&domains%5B1%5D=007import.com.br%0A&domains%5B2%5D=00pet.com.br%0A

相当于

domains[0]=0002021web.com.br
&domains[1]=007import.com.br
&domains[2]=00pet.com.br

Answer 3

0A 解码为\n 或换行； 也许先尝试消毒

$query= trim($query, "\x00..\x20\x7F");

此代码将 ASCII 字符从 00 删除到 20 hex 和 7f hex