用户在 csv/excel 报告的 sql 查询中创建 Sum/Total 行

Question

下面的查询提取数据以形成“报告”，但它基本上只是按数字分组的行项目 企业社会责任代理人。它所做的是准确无误的，在查询后我将结果保存为 CSV。然而， 它只给我个人记录，所以我必须将它放入 excel 并使用公式插入 “总计”行基本上总结了我需要总计的列。

此 sql 查询在 php 脚本中运行，但我不确定修改其中任何内容的最佳方法，以便 我可以为每个用户汇总这些列。它会以某种方式不得不说'这是用户 7200 的记录结束 因此，插入用户 7200 的总计行，然后转到用户 7206' 的记录或类似的内容。

屏幕截图显示了报告的原样，使用“x”和空空格而不是 1 或 0，所以在我的 excel 公式中 我通常有一个计数 IF "x" 变量。我希望我可以用这个脚本做类似的事情。查询和 截图如下。

这里是小提琴：http://sqlfiddle.com/#!9/b6a568/1

fiddle 的输出是精确查询的输出，唯一的区别是脚本将其放入 csv。

我只是希望有一种方法可以为每个用户创建一个“总计”行，将“x”的数量和 持续时间和保持时间的秒数。

非常感谢任何关于我如何重构它的建议。

$result = mysqli_query($conn2,
    "SELECT
          FirstN
          , LastN
        , Extension
        , Recieved
        , Recieved_Known
        , Outbound
        , Outbound_Known
        , Missed_No_VM
        , Missed_VM
        , Missed_Known
        , Calling_Number
        , Called_Number
        , Start_Time
        , End_Time
        , Talk_Time_Seconds
        , Hold_Time_Seconds

        FROM (
          SELECT distinct
           firstn
           , lastn
           , c.extension
           , CASE WHEN LEGTYPE1 = 2 AND ANSWERED = 1 THEN 'x' ELSE '' END AS Recieved
           , case when LEGTYPE1 = 2 and answered = 1 and CALLINGPARTYNO = k.phone_number then 'x' ELSE '' end as Recieved_Known
           , CASE WHEN LEGTYPE1 = 1 then 'x' ELSE '' end  AS Outbound
           , case when  FINALLYCALLEDPARTYNO = kn.long_number then 'x' ELSE '' end as Outbound_Known
           , case when legtype1 = 2 and answered = 0 and finallycalledpartyno  not like '%oice%' then 'x' ELSE '' end as Missed_No_VM
           , case when finallycalledpartyno like '%oice%' then 'x' ELSE '' end as Missed_VM
           , case when legtype1 = 2 and ANSWERED = 0 and CALLINGPARTYNO = k.phone_number then 'x' ELSE '' end as
            Missed_Known
           , a.CALLINGPARTYNO AS Calling_Number
           , a.FINALLYCALLEDPARTYNO AS Called_Number
           , b.starttime as Start_Time
           , b.endtime as End_Time
           , b.duration as Talk_Time_Seconds
           , a.holdtimesecs as Hold_Time_Seconds

          FROM ambition.session a
            INNER JOIN ambition.callsummary b ON a.NOTABLECALLID = b.NOTABLECALLID
            right join jackson_id.users c on a.callingpartyno = c.extension or a.finallycalledpartyno = c.extension
            LEFT JOIN ambition.known_numbers k ON a.callingpartyno = k.phone_number
        left join ambition.known_numbers kn on a.finallycalledpartyno = kn.long_number
                WHERE a.ts >= '2017-12-07' -- curdate()
                and(a.CALLINGPARTYNO in (select extension from ambition.ambition_users) OR a.finallycalledpartyno IN (select extension from ambition.ambition_users))
          ) x
          order by extension;") or die(mysqli_error( $conn2));

良好测量的屏幕截图：

Answer 1

我不确定您如何唯一标识用户。我假设每个用户的扩展都是唯一的。基于此，我提出以下查询：

SELECT
          Extension
        , Recieved
        , Recieved_Known
        , Outbound
        , Outbound_Known
        , Missed_No_VM
        , Missed_VM
        , Missed_Known
        , Talk_Time_Seconds
        , Hold_Time_Seconds

      FROM (
          SELECT distinct
           c.extension
           , sum(CASE WHEN LEGTYPE1 = 2 AND ANSWERED = 1 THEN 1 ELSE 0 END) AS Recieved
           , sum(case when LEGTYPE1 = 2 and answered = 1 and CALLINGPARTYNO = k.phone_number then 1 ELSE 0 end) as Recieved_Known
           , sum(CASE WHEN LEGTYPE1 = 1 then 1 ELSE 0 end)  AS Outbound
           , sum(case when  FINALLYCALLEDPARTYNO = kn.long_number then 1 ELSE 0 end) as Outbound_Known
           , sum(case when legtype1 = 2 and answered = 0 and finallycalledpartyno  not like '%oice%' then 1 ELSE 0 end) as Missed_No_VM
           , sum(case when finallycalledpartyno like '%oice%' then 1 ELSE 0 end) as Missed_VM
           , sum(case when legtype1 = 2 and ANSWERED = 0 and CALLINGPARTYNO = k.phone_number then 1 ELSE 0 end) as
            Missed_Known
           , sum(b.duration) as Talk_Time_Seconds
           , sum(a.holdtimesecs) as Hold_Time_Seconds

          FROM session a
        INNER JOIN callsummary b ON a.NOTABLECALLID = b.NOTABLECALLID
        right join users c on a.callingpartyno = c.extension or a.finallycalledpartyno = c.extension
        LEFT JOIN known_numbers k ON a.callingpartyno = k.phone_number
        left join known_numbers kn on a.finallycalledpartyno = kn.long_number
          WHERE a.ts >= '2017-12-07' -- curdate()
          and(a.CALLINGPARTYNO in (select extension from ambition_users) OR a.finallycalledpartyno IN (select extension from ambition_users))
        group by c.extension    
      ) x

          order by extension;

上面的查询，至少，会给你一些关于如何解决问题的想法。