c# Dropbox RestSharp 下载文件到流式传输

Question

我有一个“ASP.NET”控制台应用程序，并为 Dropbox 使用“RestSharp”客户端。

我使用此代码下载文件：

 var baseUrl = "https://content.dropboxapi.com";

 var client = new RestClient(baseUrl);
 client.Authenticator = OAuth1Authenticator.ForRequestToken(mc_apiKey, mc_appsecret);

 RestRequest request = new RestRequest(string.Format("/{0}/files/auto", mc_version), Method.GET);

 client.Authenticator = OAuth1Authenticator.ForProtectedResource(mc_apiKey, mc_appsecret, accessToken.Token, accessToken.Secret);
 request.AddParameter("path", path);

 var responseAccount = client.Execute(request);
 var fileString = responseAccount.Content;
 byte[] b1 = System.Text.Encoding.UTF8.GetBytes (fileString);

当调用client.Execute(request)时，整个文件被加载到内存中，所以当我在 Dropbox 中有一个非常大的文件时，程序会崩溃。

我需要让文件流式传输而不使用client.DownloadData(request).SaveAs(path) 下载到本地存储。

我需要能够分块流式传输文件。

Answer 1

你可以像这样设置 request.ResponseWriter ：

  var baseUrl = "https://content.dropboxapi.com";

  var client = new RestClient(baseUrl);
  client.Authenticator = OAuth1Authenticator.ForRequestToken(mc_apiKey,mc_appsecret);

  RestRequest request = new RestRequest(string.Format("/{0}/files/auto", mc_version), Method.GET);

  client.Authenticator = OAuth1Authenticator.ForProtectedResource(mc_apiKey, mc_appsecret, accessToken.Token, accessToken.Secret);
  request.AddParameter("path", path);

  string tempFile = Path.GetTempFileName();
  using(var stream = File.Create(tempFile, 1024, FileOptions.DeleteOnClose ))
  {
    request.ResponseWriter = (responseStream) => responseStream.CopyTo(stream);
    var response = client.DownloadData(request);
  }

您可以从文档here 中查看示例

Answer 2

我在link找到了最佳答案：

 string url = String.Format("https://content.dropboxapi.com/1/files/auto{0}?oauth_consumer_key={1}&oauth_token={2}&oauth_signature={3}%26{4}", path, app-key, access-token, app-secret, access-token-secret);
 HttpWebRequest webRequest = (HttpWebRequest)WebRequest.Create(url);
 webRequest.Method = "Get";
 WebResponse webResponse = null;
  try
  {
     webResponse = webRequest.GetResponse();
     return webResponse.GetResponseStream();
  }
  catch (Exception ex)
  {
    throw ex;       
  }