【发布时间】:2013-03-28 10:12:43
【问题描述】:
我在使用断点时收到此错误并进入捕获异常。
httpTransport.call(SOAP_ACTION, envelope);
难道httpTransport连接不应该是null?
public class MainActivity extends Activity {
TextView tv;
SoapObject request;
SoapSerializationEnvelope envelope;
HttpTransportSE androidHttpTransport;
Object result;
public String METHOD_NAME = "sum";
public String NAMESPACE = "http://ws.calculatorJava.org";
// private String SOAP_ACTION = NAMESPACE + METHOD_NAME;
public String SOAP_ACTION = "http://ws.calculatorJava.org/sum";
public static final String URL = "http://172.168.1.2:8888/CalculatotJava/services
/Calculate.wsdl";
/** Called when the activity is first created. */
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
tv = (TextView) findViewById(R.id.textView1);
try {
request = new SoapObject(NAMESPACE, METHOD_NAME);
request.addProperty("i", 5);
request.addProperty("j", 15);
envelope = new SoapSerializationEnvelope(SoapEnvelope.VER11);
envelope.dotNet = true;
envelope.setOutputSoapObject(request);
androidHttpTransport = new HttpTransportSE(URL);
Toast.makeText(getBaseContext(), "GET", Toast.LENGTH_LONG).show();
androidHttpTransport.call(SOAP_ACTION, envelope);
result = envelope.getResponse();
Toast.makeText(getBaseContext(),
" Result " + "\n" + result.toString(),
Toast.LENGTH_SHORT)
.show();
// System.out.println("Result : " + result.toString());
tv.setText("Addition : " + result.toString());
} catch (Exception E) {
E.printStackTrace();
tv.setText("ERROR " + "\n" + E.getClass().getName() + ":"
+ E.getMessage());
}
}
}
【问题讨论】:
-
尝试在浏览器中打开网址并检查是否打开
-
是的,我打开Its Fine,那里没问题,,
-
你能不能再发一次网址,因为它在我的浏览器中打不开
标签: java android web-services error-handling