无法将数据从 actionResult 发送到 mvc 中的异步方法

Question

这是我的控制器 actionReslt

[ValidateAntiForgeryToken()] 
    public ActionResult PaymentDetails(PaymentViewModel payment)
    {
        PaymentModel paymentModel = new PaymentModel();
        //  AutoMapper.Mapper.CreateMap<PaymentModel, PaymentViewModel>();
        if (ModelState.IsValid)
        {               

            CreditCardDetailsModel creditCardDetailsModel = new CreditCardDetailsModel();
            creditCardDetailsModel.SecurityId = payment.SecurityId;
            creditCardDetailsModel.ExpiryDate = payment.Month + payment.Year;
            creditCardDetailsModel.CardNumber = payment.CardNumber;
            paymentModel.CreditCardDetails = creditCardDetailsModel;
            return RedirectToAction("Payment",paymentModel);
        } 
        return View("FlightBooking");
    }

这是我的异步方法

  public async Task<JsonResult> Payment(PaymentModel model)
    {
        CreateFormOfPaymentReplyModel response = new CreateFormOfPaymentReplyModel();
        resource = Constants.Payment;
        response = await Post<CreateFormOfPaymentReplyModel>(model);

        resource = Constants.PnrConfirm;
        var pnrConformStatus = await Get<PNRConfirmResponseModel>();
        return new JsonResult { Data = new { status = false, message = response } };

    }

如果paymentObject有效但PaymentModel返回空数据并且错误显示为

This request has been blocked because sensitive information could be disclosed to third party web sites when this is used in a GET request. To allow GET requests, set JsonRequestBehavior to AllowGet

Answer 1

您是否尝试过将 allowget 传递给您的返回变量？

即：

 return Json( new { status = false, message = response }, JsonRequestBehavior.AllowGet);

希望这会有所帮助。