Python;根据用户输入打印输出

Question

这是一个简单的代码，脚本会询问用户的姓名、年龄、性别和身高，并根据这些信息给出输出。我目前的代码如下：

print "What is your name?"
name = raw_input()
print "How old are you?"
age = raw_input()
print "Are you male? Please answer Y or N"
sex = raw_input()
if sex == "Y" or sex == "y":
    sex = "Male"
else:
    sex = "Female"
print "How tall are you? Please enter in feet such as 5.5"
height = raw_input()

if sex == "Male" and height >= 6.0:
    t = "You are tall for a male"
elif sex == "Male" and height < 6.0:
    t = "You are below average for a male"

elif sex == "Female" and height >= 5.5:
    t = "You are tall for a female"
else:
    t = "You are below average for a female"


print "Hello %s. You are %s years old and %s feet tall. %s." % (name, age, height, t)

我被 if、elif、else 语句挂断了：

if sex == "Male" and height >= 6.0:
    t = "You are tall for a male"
elif sex == "Male" and height < 6.0:
    t = "You are below average for a male"

elif sex == "Female" and height >= 5.5:
    t = "You are tall for a female"
else:
    t = "You are below average for a female"

代码会区分性别是男性还是女性，但总是会返回“你高个 xxx”。我不知道如何获得“你低于平均水平”的回报。

Answer 1

那是因为raw_input() 返回的是字符串，而不是浮点数，而且 Python 2 中字符串和浮点数的比较方式始终相同。

>>> "1.0" > 6.0
True

这样做：

height = float(raw_input())

height = input() 也可以，但不鼓励（评估导致的安全问题）

注意：这已在 Python 3 中修复（可能是因为它不是很有用，而且容易出错）：尝试这样做会导致

TypeError: unorderable types: str() > float()

这是明确的，可以让你意识到你的错误。

注意：如果您尝试比较 age，同样的问题（age = raw_input() 应该是 age = int(raw_input())）