使用 SQL Server XML 导入添加索引

Question

在 SQL Server 中，我尝试使用 XML 函数导入文件，如下所示：

SELECT 
    file.value('@registrationnumber[1]', 'nvarchar(100)') AS [registrationnumber],
    report.value('@nihil[1]', 'nvarchar(100)') AS [nihil],
    report.value('@period[1]', 'nvarchar(100)') AS [period],
    report.value('@formulaid[1]', 'nvarchar(100)') AS [formulaid],
    report.value('@frequention[1]', 'nvarchar(100)') AS [frequention],
    report.value('@versieon[1]', 'nvarchar(100)') AS [version],
    variant.value('@type[1]', 'nvarchar(100)') AS [varianttype],
    variant.value('@value[1]', 'nvarchar(100)') AS [variantvalue],
    post.value('@cube[1]', 'nvarchar(100)') AS [cube],
    post.value('@row[1]', 'nvarchar(100)') AS [row],
    post.value('@rownr[1]', 'nvarchar(100)') AS [rownr],
INTO
    [#parsed]
FROM
    @xmlData.nodes('file') AS a(file)
CROSS APPLY
    file.nodes('report') AS b(report)
CROSS APPLY
    report.nodes ('post') AS c(post)
OUTER APPLY
    report.nodes ('variant') AS d(variant)

我想知道是否可以为加载的每个报告自动添加一个具有唯一索引的附加列。

我无法在谷歌上找到解决方案，因为我认为我使用了错误的搜索词。

Answer 1

使用ROW_NUMBER():

SELECT 
    file.value('@registrationnumber[1]', 'nvarchar(100)') AS [registrationnumber],
    report.value('@nihil[1]', 'nvarchar(100)') AS [nihil],
    report.value('@period[1]', 'nvarchar(100)') AS [period],
    report.value('@formulaid[1]', 'nvarchar(100)') AS [formulaid],
    report.value('@frequention[1]', 'nvarchar(100)') AS [frequention],
    report.value('@versieon[1]', 'nvarchar(100)') AS [version],
    variant.value('@type[1]', 'nvarchar(100)') AS [varianttype],
    variant.value('@value[1]', 'nvarchar(100)') AS [variantvalue],
    post.value('@cube[1]', 'nvarchar(100)') AS [cube],
    post.value('@row[1]', 'nvarchar(100)') AS [row],
    post.value('@rownr[1]', 'nvarchar(100)') AS [rownr],
    ROW_NUMBER() OVER (ORDER BY (SELECT 1)) YourSequentialIndex
INTO
    [#parsed]
FROM
    @xmlData.nodes('file') AS a(file)
        CROSS APPLY
    file.nodes('report') AS b(report)
        CROSS APPLY
    report.nodes ('post') AS c(post)
        OUTER APPLY
    report.nodes ('variant') AS d(variant)