【问题标题】:Android Async XML ParsingAndroid 异步 XML 解析
【发布时间】:2014-01-07 17:00:22
【问题描述】:

我试图从 url 解析 XML 并将其显示在列表视图上。但是,列表视图正在显示 像这样

http://postimg.org/image/ucbdjpwj5/

[我不能直接在这里发布任何图片,因为我的声誉低于 10]

这是我的代码

MainActivity

getRssDataTask ts = new getRssDataTask();
    ts.execute("http://www.xyzapp.com/feed");
}


private class getRssDataTask extends AsyncTask<String, Void, List<NewsItem>>{

    @Override
    protected List<NewsItem> doInBackground(String... params) {
        // TODO Auto-generated method stub

        try {
                // Create RSS reader
                RSSReader rssReader = new RSSReader(params[0]);

                // Parse RSS, get items
                return rssReader.getItems();

        } catch (Exception e) {
                Log.e("App", e.getMessage());
        }

        return null;
    }

    @Override
    protected void onPostExecute(List<NewsItem> result) {

        ListView Items = (ListView) findViewById(R.id.listView);

        // Create a list adapter
        ArrayAdapter<NewsItem> rs = new ArrayAdapter<NewsItem>(local,android.R.layout.simple_list_item_1, result);
        // Set list adapter for the ListView
        Items.setAdapter(rs);

RssHandler

public class RssHandler extends DefaultHandler {

    private List<NewsItem> rssItem;

    private NewsItem currentItem;

    private boolean parsingTitle;

    private boolean parsingDes;

    public RssHandler() {
        // TODO Auto-generated constructor stub

        rssItem = new ArrayList<NewsItem>();
    }

    public List<NewsItem> getItems() {
        return rssItem;
    }

    @Override
    public void startElement(String uri, String localName, String qName,
            Attributes attributes) throws SAXException {
        // TODO Auto-generated method stub
        if ("item".equals(qName)) {
            currentItem = new NewsItem();
        } else if ("title".equals(qName)) {
            parsingTitle = true;
        } else if ("content:encoded".equals(qName)) {
            parsingDes = true;
        }
    }

    @Override
    public void endElement(String uri, String localName, String qName)
            throws SAXException {
        // TODO Auto-generated method stub
        if ("item".equals(qName)) {
            rssItem.add(currentItem);
            currentItem = null;
        } else if ("title".equals(qName)) {
            parsingTitle = false;
        } else if ("content:encoded".equals(qName)) {
            parsingDes = false;
        }

    }

    @Override
    public void characters(char[] ch, int start, int length)
            throws SAXException {
        // TODO Auto-generated method stub
        if (parsingTitle) {
            if (currentItem != null)
                currentItem.setTitle(new String(ch, start, length));
        } else if (parsingDes) {
            if (currentItem != null) {
                currentItem.setDes(new String(ch, start, length));
                parsingDes = false;
            }
        }
    }
}

RssReader

public class RSSReader {

    private String RssUrl;
    public RSSReader(String RssUrl) {
        // TODO Auto-generated constructor stub
        this.RssUrl = RssUrl;
    }

    public List<NewsItem> getItems() throws Exception{

        SAXParserFactory factory = SAXParserFactory.newInstance();
        SAXParser saxParser = factory.newSAXParser();

        RssHandler handler = new RssHandler();

        saxParser.parse(RssUrl, handler);

        return handler.getItems();

    }
}

我无法找出问题所在。我的问题是我做错了什么?

【问题讨论】:

  • 你需要在NewsItem中覆盖toString()

标签: android xml xml-parsing android-asynctask


【解决方案1】:

在 NewsItem 中实现以下方法:

@Override
public String toString() {
  // return a String value representing this object
  // Assuming two class String properties called title and description
  return title + ": " + description;
}

【讨论】:

  • 我有两个字符串标题和描述。如何同时返回两个字符串?
  • 已编辑答案。假设您的类中有两个 String 属性。如何创建要返回的格式化字符串值取决于您。我使用了 ':' 字符来分隔 2 个字符串
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