多个匹配的 SQL 语义相似性表

Question

我正在对 1000 个文档进行语义分析。我想要每个文档的前 5 个匹配项。这是我正在使用的查询；

DECLARE @FTE hierarchyid
SELECT @FTE = path_locator
   from dbo.LatinBooks

Select top (5)
 e.name
,d.name as MatchedFTE
,KEY_TBL.score
FROM SEMANTICSIMILARITYTABLE
     (dbo.LatinBooks,
      file_stream,
      @FTE ) as KEY_TBL
 INNER JOIN dbo.LatinBooks d on KEY_TBL.matched_document_key= d.path_locator
 left Join (select path_locator,name from dbo.LatinBooks) e on @fte=e.path_locator 
Order by Key_tbl.score DESC;

此查询有效，它返回第一个文档的最高匹配项。我可以对脚本进行哪些更改，它将返回所有 1000 个文档的匹配项。结果将显示 5,000 行（一个文档和五个匹配项）

Answer 1

你想要row_number():

select *
from (Select e.name, d.name as MatchedFTE, KEY_TBL.score,
             row_number() over (partition by e.name order by KEY_TBL.score desc) as seqnum
      from SEMANTICSIMILARITYTABLE(dbo.LatinBooks,file_stream, @FTE
                                  ) KEY_TBL INNER JOIN
           dbo.LatinBooks d
           on KEY_TBL.matched_document_key = d.path_locator left Join
           dbo.LatinBooks e
           on @fte = e.path_locator 
     ) x
where seqnum <= 5;