如何在Java中绘制字符[关闭]

Question

程序要打印符号的矩形的长度和宽度 例如

*****
*   *
*   *
*   *
*   *
*****

Answer 1

你可以通过你的逻辑来解决这个问题。你可以看到下面的源代码：

import java.util.Scanner;

public class Piramd1 {

    public static void main(String args[]) {

        Scanner conin = new Scanner(System.in);
        System.out.print("How many lines=");
        int n = conin.nextInt();

        for (int r = 1; r <= n; r++) {
            for (int c = 1; c <= n; c++) {

                if (r == 1 || r == n || c == 1 || c == n) {
                    System.out.print("*");
                } else {
                    System.out.print(" ");
                }
            }
           System.out.println();
        }
    }
}

Answer 2

使用逻辑检查迭代为二维数组：

public static void rectOuter(int length, int width) {

    String printStr = "*";
    String seprator = " ";

    for (int i = 0; i < length; i++) {

        for (int j = 0; j < width; j++)

            if (i == 0 || j == 0 || i == length - 1 || j == width - 1)
                System.out.print(printStr + seprator);
            else
                System.out.print(seprator + seprator);

        System.out.println();
    }
}

PS：System.out.print 被 StringBuilder 替换