python Tkinter下拉菜单的问题

【问题标题】：issue with python Tkinter drop down menupython Tkinter下拉菜单的问题
【发布时间】：2012-06-22 15:08:09
【问题描述】：

以下代码是将按钮附加到现有程序上的程序，因此可以在更友好的界面上而不是在代码内部进行选择。我正在尝试使用下拉菜单，但 setEthAnt1 函数似乎有错误：TypeError: setEthAnt1() 不接受任何参数（给定 1）。我不知道我没有传入什么参数。有人有什么想法吗？

from Tkinter import *
import ThreegroupsGraphics as three

def run():
    three.main()

def setEthAnt1():
    name = var.get()
    print name
    three.OneTo2Ant = name
    print three.OneTo2Ant

root = Tk()
var = StringVar()
var.set("Group 1 Ethnic Antagonism")
OptionMenu(root, var, "1","2","3","4","5","6","7","8","9","10", command = setEthAnt1).pack()
butn = Button(root, text = 'run',  command = run)
butn.pack()
root.mainloop()

【问题讨论】：

标签： python tkinter arguments drop-down-menu

【解决方案1】：

当您为 OptionMenu 指定命令时，所选项目的值将被发送到命令中，这实际上使您的 var.get() 不再需要。见下文：

from Tkinter import *
import ThreegroupsGraphics as three

def run():
    three.main()

def setEthAnt1(name):
    print name
    three.OneTo2Ant = name
    print three.OneTo2Ant

root = Tk()
var = StringVar()
var.set("Group 1 Ethnic Antagonism")
OptionMenu(root, var, "1","2","3","4","5","6","7","8","9","10", command = setEthAnt1).pack()
butn = Button(root, text = 'run',  command = run)
butn.pack()
root.mainloop()

如果你不希望setEthAnt1 有任何参数并且仍然使用var.get()，你可以像这样将OptionMenu 的命令变成一个lamda 函数：

OptionMenu(root, var, "1","2","3","4","5","6","7","8","9","10", command = lambda _: setEthAnt1).pack()

【讨论】：