【发布时间】：2014-03-21 14:03:19
【问题描述】：
我有以下代码：
/*****************************************************************/
/* */
/* Program Greated By: Dani Smith */
/* Dr. Azzar Introduction to Computer Science */
/* Spring 2014 */
/* Due Date: March 19, 2014 (Extended to March 24, 2014) */
/* Lab 2: Array Processing */
/* This program places information from an infile into */
/* arrays, processes those arrays, and then prints the */
/* processed information to an outfile. */
/* */
/*****************************************************************/
/***********************Include Statements************************/
/**/ #include <iostream> /**/
/**/ #include <iomanip> /**/
/**/ #include <fstream> /**/
/**/ #include <string> /**/
/**/ #include <stdio.h> /**/
/**/ #include <cstdlib> /**/
/*****************************************************************/
//Other Pre-declerations
using namespace std;
/*********************Function Prototypes**************************/
int process_employee(ifstream&, int[], string[], double[]);
int process_payroll(ifstream&, int[], string[], double[]);
void print_results(ifstream&, ofstream&, int[], string[], double[], int);
int highest_pay(double[], int);
int lowest_pay(double[], int);
/******************************************************************/
int main(){
typedef int intArray[15];
double wage[15];
string name[15];
intArray hours;
int i = 0, j, index;
ifstream inFile;
ofstream outFile;
//opens the files that will be used in the program
inFile.open("C:/Users/Dani Smith/Documents/lab2In.txt");
outFile.open("C:/Users/Dani Smith/Documents/lab2out.txt");
//displays error message if one or both of the files failed to open
if (inFile.fail()){
cout << "Cannot find input file" << endl;
exit(1);
}
if (outFile.fail()){
cout << "Cannot find output file" << endl;
system("pause");
exit(1);
}
i = process_employee(inFile, hours, name, wage); //this is what I am trying to move into the print_results function
//Call Process Payroll
//Print Items
print_results(inFile, outFile, hours, name, wage, i);
//system("start C:/Users/Dani Smith/Documents/lab2out.txt");
return 1;
}
int process_employee(ifstream& in, int hours[], string name[], double wage[]){
int i = 0;
while (in >> name[i] >> wage[i] >> hours[i])
i++;
return i;
}
//highest_pay finds the highrest payed worker.
int highest_pay(double rate[], int items){
double high = -9999;
int y = 0, highIndex = 0;
for (y = 0; y < items; y++)
if (rate[y] > high){
high = rate[y];
highIndex = y;
}
return highIndex;
}
//lowest_pay finds the lowest payed worker.
int lowest_pay(double rate[], int items){
double low = 9999;
int y = 0, lo`wIndex = 0;
for (y = 0; y < items; y++)
if (rate[y] < low){
low = rate[y];
lowIndex = y;
}
return lowIndex;
}
//calculate how much each employee should be paid
int process_payrol(ifstream& in, int hours[], string name[], double wage[]){
}
//prints the report to the outfile
void print_results(ifstream& in, ofstream& out, int hours[], string name[], double wage[], int empNum){
int j, index i = empNum;
out << "Number of Employees: " << i << endl; //prints the number of employees
index = highest_pay(wage, i);//changes index to the highest pay rate
out << "Maximum Pay Rate: " << name[index] << " @ $" << wage[index] << endl;//prints the maximum pay rate
index = lowest_pay(wage, i);//changes index to the lowest pay rate
out << "Minimum Pay Rate: " << name[index] << " @ $" << wage[index] << endl;//prints the minimum pay rate
//prints the titles on the top of the outfile
out << endl << setw(15) << "Name" << setw(8) << "Hours" << setw(8) << "Gross" << setw(7) << "Bonus" << setw(19) << "Adjusted Gross\n" << endl;
//for loop prints the rest of the report
for (j = 0; j < i; j++)
out << setw(15) << name[j] << setw(8) << hours[j] << setw(8) << hours[j] << endl;
system("pause");
}
我正在尝试将 int i 从 int main 函数移动到 print_results 函数中。当我这样做时
int i = process_employee(in, hours, name, wage);
int i 仍然为 0。所以我的问题是如何使用 c++ 中第一个函数的参数在函数中调用函数。另外，另一个问题是如何在程序结束时启动 outFile？我试图做一个系统（“这里的开始路径”）;，但它找不到文件，因为路径中有空格。所以在夏天我有两个问题： 1. 如何使用第一个函数的参数调用函数内的函数？ 2. 如何打开路径中有空格的txt文件？
【问题讨论】：
-
嘿，这样一个伟大的标题和如此糟糕的格式。第二个答案是
\" -
标题看起来很有趣，但这种包含风格不太可能赢得任何赞赏奖。
-
博士。 Azzar 会很高兴他的学生在 Stack Overflow 上完成作业
-
@BartekBanachewicz 根据标准
#必须是第一个字符 -
@MaciejLichoń 与我今天看到的其他家庭作业问题不同，这个问题至少有提问者提出的相当多的努力。我最近看到了几个简单的任务剪切和粘贴，没有其他明显的努力。