Android - 数据不会发布到 PHP 脚本

Question

美好的一天！

我的 android 应用程序需要将 POST 数据发送到 PHP 脚本，但是该脚本没有检测到正在发送的数据。由于我对 Java Android 编程比较陌生，如果我忽略了一个简单的概念，请原谅我。

由于我从未涉足过ajax，我想要一个不实现ajax 的解决方案，这就是为什么“Get post data from Android to PHP”和“Posting data from android to PHP”中的解决方案不符合我想要的解决方案的原因.

下面是我的相关源码：

插入Contact.java

public void sendRequest() {
    SendtoPHP sendtoPHP = new SendtoPHP();
    sendtoPHP.execute(new String[] {
            "https://a/foo.php"
    });
}

private class SendtoPHP extends AsyncTask<String, Void, String> {
    @Override
    protected String doInBackground(String... urls) {
        BufferedReader reader = null;
        String text = "";

        try {
            String data = URLEncoder.encode("contactNo=98765432", "UTF-8");
            String type = "application/x-www-form-urlencoded";

            URL url = new URL(urls[0]);
            HttpURLConnection conn = (HttpURLConnection) url.openConnection();
            conn.setDoOutput(true);
            conn.setRequestMethod("POST");
            conn.setRequestProperty("Content-Type", type);
            conn.setRequestProperty("Content-Length", String.valueOf(data.length()));
            OutputStream outputStream = conn.getOutputStream();
            outputStream.write(data.getBytes());

            System.out.println("test success!");
            // server response
            reader = new BufferedReader(new InputStreamReader(conn.getInputStream()));
            StringBuilder sb = new StringBuilder();
            String line = null;

            // Read Server Response
            while ((line = reader.readLine()) != null) {
                // Append server response in string
                sb.append(line + "\n");
            }

            text = sb.toString();
        } catch (Exception e) {
            System.out.println(e);
        } finally {
            try {
                reader.close();
                return text;
            } catch (Exception e) {
                System.out.println(e);
                return "Failed to close reader.";
            }
        }
    }
    @Override
    protected void onPostExecute(String result) {
        System.out.println(result);
        System.out.println("SUCCESS!");
    }
}

foo.php

<?php
    if (isset($_POST['contactNo'])) {
        $contactNo = $_POST['contactNo'];

        //require_once 'dbHandler.php';
        //$con = new dbConnect();
        $querymysql = new mysqli("my_db_ip", "my_username", "my_password", "my_db");
        $result = $querymysql -> query("call insertContacts($contactNo)");

        if ($result) {
            echo "Insert successful!";
        } else {
            echo "Insert failed!";
        }

        $result -> close();
        $querymysql -> close();

    } else {
        echo "Hi! Welcome to foo.php. You have reached a dead end as you are physically connecting
        to our backend scripts.<br/>This page will unfortunately serve you no purpose. Sorry for the inconvenience
         caused.";
    }

Android Studio 控制台日志

I/System.out: test success!
I/System.out: Hi! Welcome to foo.php. You have reached a dead end as you are physically connecting
I/System.out:         to our backend scripts.<br/>This page will unfortunately serve you no purpose. Sorry for the inconvenience
I/System.out:          caused.
I/System.out: SUCCESS!

正如我们从控制台日志中看到的，POST 数据没有发送到 PHP 脚本，因为出现了不需要的回显消息。

任何帮助将不胜感激！ :)

编辑：

我已经包含了根据@FerryBig 的答案修改我的代码后出现的错误的堆栈跟踪。

W/System.err: java.io.FileNotFoundException: https://a/foo.php
W/System.err:     at com.android.okhttp.internal.huc.HttpURLConnectionImpl.getInputStream(HttpURLConnectionImpl.java:250)
W/System.err:     at com.android.okhttp.internal.huc.DelegatingHttpsURLConnection.getInputStream(DelegatingHttpsURLConnection.java:210)
W/System.err:     at com.android.okhttp.internal.huc.HttpsURLConnectionImpl.getInputStream(HttpsURLConnectionImpl.java)
W/System.err:     at name.calvin.testdbconnect.insertContact$SendtoPHP.doInBackground(insertContact.java:62)
W/System.err:     at name.calvin.testdbconnect.insertContact$SendtoPHP.doInBackground(insertContact.java:41)
W/System.err:     at android.os.AsyncTask$2.call(AsyncTask.java:305)
W/System.err:     at java.util.concurrent.FutureTask.run(FutureTask.java:237)
W/System.err:     at android.os.AsyncTask$SerialExecutor$1.run(AsyncTask.java:243)
W/System.err:     at java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1133)
W/System.err:     at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:607)
W/System.err:     at java.lang.Thread.run(Thread.java:761)

Answer 1

当向网络服务器发送数据时，您应该非常接近specifications。它说你应该使用=作为数据的分隔符，当你把它包含在你的数据中时，你不小心把它通过urlencoder，改变了字符。

通过更改urlencoder分别对key侧（左）和value侧（右）进行编码，它将正确发送数据。

String data = URLEncoder.encode("contactNo", "UTF-8") 
            + "=" 
            + URLEncoder.encode("98765432", "UTF-8");