【发布时间】：2013-12-10 18:00:05
【问题描述】：
我已经搜索了一天的解决方案，但找不到适合我情况的解决方案。我很抱歉，但我是 JSON（自学程序员）的新手，我不知道我应该只发布哪些课程，所以我会投入我所拥有的一切。我从 LogCat 收到以下错误：
Error parsing data org.json.JSONException: Value <?xml of type java.lang.String cannot be converted to JSONArray
这是我的课：
package com.example.mytravelbuddy;
import android.os.AsyncTask;
import android.os.Bundle;
import android.app.Activity;
import android.app.ProgressDialog;
import android.util.Log;
import android.view.Menu;
import android.widget.ImageView;
import android.widget.ListAdapter;
import android.widget.ListView;
import android.widget.SimpleAdapter;
import android.widget.Toast;
import java.util.ArrayList;
import java.util.HashMap;
import java.util.List;
import org.apache.http.NameValuePair;
import org.json.JSONArray;
import org.json.JSONException;
import org.json.JSONObject;
public class Itinerary extends Activity {
// Progress Dialog
private ProgressDialog pDialog;
//JSON Parser
JSONParser jParser = new JSONParser();
//URL To Get Products
public static String url = "URL REMOVED"; //Removed my url since i was hosting online
//JSON Node names
private static final String TAG_SUCCESS = "success";
private static final String TAG_ITEMS = "items";
private static final String TAG_ID = "ID";
private static final String TAG_LOCATION = "Location";
private static final String TAG_DESCRIPTION = "Description";
private static final String TAG_LATITUDE = "Latitude";
private static final String TAG_LONGITUDE = "Longitude";
private static final String TAG_TIME = "Time";
//Array list
ArrayList<HashMap<String, String>> itemList;
//Items JSONArray
JSONArray items = null;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_starting_point);
itemList = new ArrayList<HashMap<String, String>>();
new LoadAllItems().execute();
}
@Override
public boolean onCreateOptionsMenu(Menu menu) {
// Inflate the menu; this adds items to the action bar if it is present.
getMenuInflater().inflate(R.menu.starting_point, menu);
return true;
}
class LoadAllItems extends AsyncTask<String, String, String>{
@Override
protected void onPreExecute() {
super.onPreExecute();
pDialog = new ProgressDialog(Itinerary.this);
pDialog.setMessage("Loading items. Please wait...");
pDialog.setIndeterminate(false);
pDialog.setCancelable(false);
pDialog.show();
}
@Override
protected String doInBackground(String... arg0) {
//Building Params
List<NameValuePair> params = new ArrayList<NameValuePair>();
//Getting JSON String
JSONObject json = jParser.makeHttpRequest(url, "GET", params);
try{
//Getting array of items
Log.i("Error","ERROR 1"); //This error message is displayed
items = json.getJSONArray(TAG_ITEMS); //This is the line that is giving me a problem
Log.i("Error","ERROR 2"); //This error message is not displayed
//Looping through
for(int i = 0; i < items.length();i++){
JSONObject c = items.getJSONObject(i);
//Storing JSON item in variable
String location = c.getString(TAG_LOCATION);
String description = c.getString(TAG_DESCRIPTION);
String longitude = c.getString(TAG_LONGITUDE);
String latitude = c.getString(TAG_LATITUDE);
String time = c.getString(TAG_TIME);
//Creating HashMap
HashMap<String, String> map = new HashMap<String, String>();
//Put value in hashmap map
map.put(TAG_LOCATION, location);
map.put(TAG_DESCRIPTION, description);
map.put(TAG_LONGITUDE, longitude);
map.put(TAG_LATITUDE, latitude);
map.put(TAG_TIME, time);
itemList.add(map);
}
}catch(JSONException e){
e.printStackTrace();
}
return null;
}}
}
通过在 LogCat 中显示错误消息，我发现在哪一行出现错误。
这是我试图从中获取响应的 PHP 文件：
<?php
$user = "root";
$pass = "";
$database = "travel_buddy";
$server = "127.0.0.1";
mysql_connect($server, $user, $pass);
$db_found = mysql_select_db($database);
if($db_found){
echo"DB Found<br>";
}else{
echo"DB NOT Found<br>";
}
echo"Connection Established<br>";
get_details();
function get_details(){
$response = array();
$result = mysql_query("SELECT *FROM adventure");
if(mysql_num_rows($result)>0){
$response["items"] = array();
while($row = mysql_fetch_array($result)){
$info = array();
$product["ID"] = $row["ID"];
$product["Location"] = $row["Location"];
$product["Description"] = $row["Description"];
$product["Latitude"] = $row["Latitude"];
$product["Longitude"] = $row["Longitude"];
$product["Time"] = $row["Time"];
array_push($response["items"], $product);
}
$response["success"] = 1;
echo json_encode($response);
} else {
$response["success"] = 0;
$response["message"] = "No Information Found";
echo json_encode($response);
}
}
?>
这是我的 JSON 响应：
{
"items": [
{
"ID": "1",
"Location": "TEST",
"Description": "TEST DESC",
"Latitude": "1",
"Longitude": "2",
"Time": "3:00"
},
{
"ID": "2",
"Location": "TEST2",
"Description": "TEST2 DESC",
"Latitude": "1",
"Longitude": "1",
"Time": "7:00"
},
{
"ID": "3",
"Location": "TEST3",
"Description": "TEST3 DESC",
"Latitude": "3",
"Longitude": "4",
"Time": "12:00"
}
],
"success": 1
}
这是我的 JSON 解析器类：
package com.example.mytravelbuddy;
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.io.UnsupportedEncodingException;
import java.util.List;
import org.apache.http.HttpEntity;
import org.apache.http.HttpResponse;
import org.apache.http.NameValuePair;
import org.apache.http.client.ClientProtocolException;
import org.apache.http.client.entity.UrlEncodedFormEntity;
import org.apache.http.client.methods.HttpGet;
import org.apache.http.client.methods.HttpPost;
import org.apache.http.client.utils.URLEncodedUtils;
import org.apache.http.impl.client.DefaultHttpClient;
import org.json.JSONException;
import org.json.JSONObject;
import android.util.Log;
public class JSONParser {
static InputStream is = null;
static JSONObject jObj = null;
static String json = "";
// constructor
public JSONParser() {
}
// function get json from url
// by making HTTP POST or GET mehtod
public JSONObject makeHttpRequest(String url, String method,
List<NameValuePair> params) {
// Making HTTP request
try {
// check for request method
if(method == "POST"){
// request method is POST
// defaultHttpClient
DefaultHttpClient httpClient = new DefaultHttpClient();
HttpPost httpPost = new HttpPost(url);
httpPost.setEntity(new UrlEncodedFormEntity(params));
HttpResponse httpResponse = httpClient.execute(httpPost);
HttpEntity httpEntity = httpResponse.getEntity();
is = httpEntity.getContent();
}else if(method == "GET"){
// request method is GET
DefaultHttpClient httpClient = new DefaultHttpClient();
String paramString = URLEncodedUtils.format(params, "utf-8");
url += "?" + paramString;
HttpGet httpGet = new HttpGet(url);
HttpResponse httpResponse = httpClient.execute(httpGet);
HttpEntity httpEntity = httpResponse.getEntity();
is = httpEntity.getContent();
}
} catch (UnsupportedEncodingException e) {
e.printStackTrace();
} catch (ClientProtocolException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
try {
BufferedReader reader = new BufferedReader(new InputStreamReader(
is, "iso-8859-1"), 8);
StringBuilder sb = new StringBuilder();
String line = null;
while ((line = reader.readLine()) != null) {
sb.append(line + "\n");
}
is.close();
json = sb.toString();
} catch (Exception e) {
Log.e("Buffer Error", "Error converting result " + e.toString());
}
// try parse the string to a JSON object
try {
jObj = new JSONObject(json);
} catch (JSONException e) {
Log.e("JSON Parser", "Error parsing data " + e.toString());
}
// return JSON String
return jObj;
}
}
任何帮助都会非常有帮助，可能会解释为什么我会出现此错误，因此我不再重复。
【问题讨论】：
-
您似乎收到的是 XML 而不是 JSON。
-
这
method == "GET"也是错误的。比较字符串时使用.equals。 -
是的，我知道那部分。我不知道如何解决它？是不是我的数据库有问题？
-
@SotiriosDelimanolis 这是一个预制的解析器类...感谢您指出这一点:)
-
请don't use mysql_* functions in new code。它们不再被维护并被正式弃用。改为了解prepared statements，并使用PDO 或MySQLi — this article 将帮助您决定哪个。如果你选择 PDO，here is a good tutorial.