配置单元中的日期差异，差异应该在 hh:mm:ss

Question

我试图找出连续行中两个日期之间的差异。我在 hive 中使用窗口函数，即lag。

但不同之处，即输出格式应为hh:mm:ss。

例如：

• 日期 1 是 2017-08-15 02:00:32
• 日期 2 是2017-08-15 02:00:20

输出应该是：

00:00:12

我尝试的查询：

select from_unixtime(column_name),
(lag(unix_timestamp(from_unixtime(column_name)),1,0)
over(partition by column_name)-
unix_timestamp(from_unixtime(column_name))) as Duration from table_name;

但这会将输出返回为12（在上面的示例中）。

更新

我已将该列存储在具有 bigint 数据类型的表中。时间采用纪元格式。我们在查询中使用 from_unixtime 将其转换为可读日期。时间戳中的示例值

1502802618 1502786788

Answer 1

hive> with t as (select 1502802618 as ts1,1502786788 as ts2)
    > select  printf('%02d:%02d:%02d',(ts1 - ts2) div 3600,((ts1 - ts2) % 3600) div 60,((ts1 - ts2) % 3600) % 60) as diff
    > from    t
    > ;
OK
diff
04:23:50

Answer 2

只要时差小于 24 小时，答案就是相关的

hive> with t as (select 1502802618 as ts1,1502786788 as ts2)
    > select  from_unixtime(to_unix_timestamp('0001-01-01 00:00:00')+(ts1 - ts2))  as diff
    > from    t
    > ;
OK
diff
0001-01-01 04:23:50

---

hive> with t as (select 1502802618 as ts1,1502786788 as ts2)
    > select  substr(from_unixtime(to_unix_timestamp('0001-01-01 00:00:00')+(ts1 - ts2)),12)   as diff
    > from    t
    > ;
OK
diff
04:23:50

Answer 3

只要时差小于 24 小时，答案就是相关的

hive> with t as (select timestamp '2017-08-15 02:00:32' as ts1,timestamp '2017-08-15 02:00:20' as ts2)
    > select  ts1 - ts2   as diff
    > from    t
    > ;
OK
diff
0 00:00:12.000000000

给定时间戳

hive> with t as (select timestamp '2017-08-15 02:00:32' as ts1,timestamp '2017-08-15 02:00:20' as ts2)
    > select  split(ts1 - ts2,'[ .]')[1]  as diff
    > from    t
    > ;
OK
diff
00:00:12

给定字符串

hive> with t as (select '2017-08-15 02:00:32' as ts1,'2017-08-15 02:00:20' as ts2)
    > select  split(cast(ts1 as timestamp) - cast(ts2 as timestamp),'[ .]')[1]  as diff
    > from    t
    > ;
OK
diff
00:00:12