无法从 PHP 中的 facebook signedRequest 获取用户 ID。答案

【问题标题】：Can't get user id from facebook signedRequest in PHP .无法从 PHP 中的 facebook signedRequest 获取用户 ID。
【发布时间】：2013-07-25 17:12:31
【问题描述】：

在我的索引页面上，我初始化了 javascript sdk 并完成了登录/授权流程。然后我使用 AJAX 将签名的请求传递给我的 php 页面进行解析。解析签名请求的代码是直接从文档中复制过来的，我没有做任何改动。在该代码的末尾，我尝试获取在与签名请求相同的对象中返回的用户信息，但是当我尝试在 AJAX 成功回调中记录任何这些变量时，它们会出现“未定义”。

//HTML

function onCheckLoginStatus (response)
    {
     if (response.status != "connected")
     {
      //redirect to login page;
     }
     else
     {

     //CONNECTED, Get signed request from response object and pass it to PHP page via AJAX

      $.ajax({
        url : "http://XXXXXXX/bn/signedRequest.php",
        type : 'POST',
        data: {signed_request: response.authResponse.signedRequest},
        success : function (result) {

           console.log("success"); 

           //THIS IS COMING UP UNDEFINED 

                console.log(result.uID);
        },
        error : function () {
           alert("error");
        }
    });

//PHP    
<?php

define('FACEBOOK_APP_ID', '27XXXXXX0&'); // Place your App Id here
define('FACEBOOK_SECRET', '8ea907XXXXXXX9e958'); // Place your App Secret Here

//GET THE SIGNED REQUEST

$signed_request = $_REQUEST['signed_request']; 



function parse_signed_request($signed_request, $secret) 
{
list($encoded_sig, $payload) = explode('.', $signed_request, 2);
// decode the data
$sig = base64_url_decode($encoded_sig);
$data = json_decode(base64_url_decode($payload), true);
if (strtoupper($data['algorithm']) !== 'HMAC-SHA256')
{
error_log('Unknown algorithm. Expected HMAC-SHA256');
return null;
}


// check sig
$expected_sig = hash_hmac('sha256', $payload, $secret, $raw = true);
if ($sig !== $expected_sig) 
{
error_log('Bad Signed JSON signature!');
return null;
}
return $data;
}
function base64_url_decode($input) 
{
return base64_decode(strtr($input, '-_', '+/'));
}

if ($_REQUEST) 
{
$response = parse_signed_request($_REQUEST['signed_request'],
FACEBOOK_SECRET);
}


$uID = $response["user_id"];
$name = $response["registration"]["name"]; 
$city = $response["registration"]["location"]["name"];

echo json_encode($uID);



?>

【问题讨论】：

标签： jquery facebook-javascript-sdk facebook-php-sdk

【解决方案1】：

要么发送整个$response

或

将回显线改为

echo($uID);

并将 AJAX 调用中的 console.log 行更改为

console.log(result);

您可以通过记录结果来验证自己

 $.ajax({
        url : "http://XXXXXXX/bn/signedRequest.php",
        type : 'POST',
        data: {signed_request: response.authResponse.signedRequest},
        success : function (result) {

           console.log("success"); 

           //THIS IS COMING UP UNDEFINED 

           console.log(result); // <----- Check whether result is undefined
        },
        error : function () {
           alert("error");
        }
    });

【讨论】：