【发布时间】:2014-01-24 10:04:09
【问题描述】:
<a class="btn btn-primary" id="popover">xxx</a></li>
<div id="popover-head" class="hide"><h3 class="popover-title" style="color:#333;">xxx</h3></div>
<div id="popover-content" class="hide">
<?php
// check for a successful form post
if (isset($_GET['s'])) echo "<div class=\"alert alert-success\">".$_GET['s']."</div>";
// check for a form error
elseif (isset($_GET['e'])) echo "<div class=\"alert alert-danger\">".$_GET['e']."</div>";
?>
<form role="form" method="POST" action="*.php">
<div class="row">
<div class="form-group col-lg-12">
<label for="input1">Name</label>
<input type="text" name="contact_name" class="form-control" id="input1">
</div>
</div>
<div class="row">
<div class="form-group col-lg-12">
<label for="input2">Email Address</label>
<input type="email" name="contact_email" class="form-control" id="input2">
</div>
</div>
<div class="row">
<div class="form-group col-lg-12">
<label for="input3">Phone Number</label>
<input type="phone" name="contact_phone" class="form-control" id="input3">
</div>
</div>
<div class="clearfix"></div>
<div class="form-group col-lg-12">
<label for="input4">We will be in touch soon!</label>
<textarea name="contact_message" rows="6" style="display:none" class="form-control" id="input4">xxx</textarea>
</div>
<div class="form-group col-lg-12">
<input type="hidden" name="save" value="contact">
<button type="submit" class="btn btn-primary">Submit</button>
</div>
</div>
</form>
这段代码有 2 个问题。第一个问题是,当我将表单插入 bootstrap3 弹出框时,它会中断。第二个问题是弹出框不会打开。如果我从中删除代码,弹出框会打开,如果它不在弹出框内,则 php 脚本会运行。
【问题讨论】:
标签: php twitter-bootstrap twitter-bootstrap-3 popover contact-form