在特定范围内对列表进行四舍五入

Question

我有一个数字列表，我希望以某种方式将其转换为单位步进形式

这些是我的界限

[367.3090551181102, 371.73179133858264, 376.1545275590551, 380.5772637795276, 385.0]

这是我的数据

[367.3090551181102, 370, 370, 370, 370, 370, 370, 370, 369, 369, 369, 369, 369, 369, 369, 369, 369, 369, 369, 369, 368, 369, 368, 368, 368, 368, 368, 368, 368, 368, 369, 370, 367.3090551181102, 367.3090551181102, 367.3090551181102, 370, 368, 373, 369, 371, 368, 367.3090551181102, 367.3090551181102, 367.3090551181102, 369, 367.3090551181102, 372, 367.3090551181102, 368, 368, ...]

我想要做的是基本上将数据中的每个数字向下或向上舍入到边界。数字在下边界和上边界之间。

假设数字是 370，我想将它四舍五入到 371.73... 因为它在 367.309... 和 371.73... 之间，或者数字是 381，那么我想将它四舍五入到 370.57...

这是我的代码，但我有点困惑

def unit_step(data,boundaries):
    us = []
    for d in data:
        if(boundaries[0] < d < boundaries[1]):
            us.append(rounder(boundaries[0],boundaries[1],d))
        elif(boundaries[1] < d < boundaries[2]):
            us.append(rounder(boundaries[1],boundaries[2],d))
        elif(boundaries[2] < d < boundaries[3]):
            us.append(rounder(boundaries[2],boundaries[3],d))
        elif(boundaries[3] < d < boundaries[4]):
            us.append(rounder(boundaries[3],boundaries[4],d))
    return us

我在另一个 for 循环中尝试了 for 循环，但没有成功。

我哪里错了，或者与双循环相比它是一种有用的方法吗？

Answer 1

您可以使用带有min 的列表推导来检查boundaries 中最接近（较高 或 较低）的值，并相应地替换data 中的值

>>> [min(boundaries, key=lambda i: abs(i - value)) for value in data]
[367.3090551181102, 371.73179133858264, 371.73179133858264, 371.73179133858264, 371.73179133858264, 371.73179133858264, 371.73179133858264, 371.73179133858264, 367.3090551181102, 367.3090551181102, 367.3090551181102, 367.3090551181102, 367.3090551181102, 367.3090551181102, 367.3090551181102, 367.3090551181102, 367.3090551181102, 367.3090551181102, 367.3090551181102, 367.3090551181102, 367.3090551181102, 367.3090551181102, 367.3090551181102, 367.3090551181102, 367.3090551181102, 367.3090551181102, 367.3090551181102, 367.3090551181102, 367.3090551181102, 367.3090551181102, 367.3090551181102, 371.73179133858264, 367.3090551181102, 367.3090551181102, 367.3090551181102, 371.73179133858264, 367.3090551181102, 371.73179133858264, 367.3090551181102, 371.73179133858264, 367.3090551181102, 367.3090551181102, 367.3090551181102, 367.3090551181102, 367.3090551181102, 367.3090551181102, 371.73179133858264, 367.3090551181102, 367.3090551181102, 367.3090551181102]