根据列名（多维数组）获取选定的行：Javascript [重复]

Question

我有一个多维数组，如下所示：

[
["1","success","5"],
["2","success","5"],
["3","success","5"],
["4","fail","5"],
["5","fail;","5"],
["6","fail","5"],
["7","success","5"],
["8","fail","5"],
];

我需要的是根据success 和fail 类型选择特定的行。这意味着对于 eaxmple，我必须只获取第二列名为 success的数据

我已经编写了一个代码，但它在单独的数组中为我提供了值。 我想要这种格式的数据

 [
    ["1","success","5"],
    ["2","success","5"],
    ["3","success","5"],
    ["7","success","5"],
]

我尝试过的代码如下：

  var success = [];
     for(var i=0;i<arr.length;i++)
     {
        if(arr[i][1] =='success')
        {
         success = [arr[i]];
         console.log(success);
        }
     }

我想要单个数组中的所有数据。 这是我尝试过的小提琴链接：https://jsfiddle.net/abnitchauhan/09zchjak/

Answer 1

您可以使用array filter 方法。

const data = [
  ['1', 'success', '5'],
  ['2', 'success', '5'],
  ['3', 'success', '5'],
  ['4', 'fail', '5'],
  ['5', 'fail;', '5'],
  ['6', 'fail', '5'],
  ['7', 'success', '5'],
  ['8', 'fail', '5'],
];
const success = data.filter((x) => x[1] === 'success');
console.log(success);