循环遍历数组 - 仅第一个索引打印

Question

我想遍历一个数组并打印任何不为空的值，这是我尝试使用的代码：

for (int i = 0; i < 10; i++) {
  if (studentNamesArray[i] != null) {
    studentFound = true;
    System.out.println("Which student would you like to delete?");
    System.out.println(i + ": " + studentNamesArray[i]);
    int studentChoice = input.nextInt();
  }
}

数组：

static String[] studentNamesArray = new String[10];

问题是它只打印出index[0]。我该如何解决这个问题？

编辑：

这是我的完整代码：

  static void deleteStudent() {
    boolean studentFound = false;
    for (int i = 0; i < 10; i++) {
      if (studentNamesArray[i] != null) {
        studentFound = true;
        System.out.println("Which student would you like to delete?");
        System.out.println(i + ": " + studentNamesArray[i]);
      }
        int studentChoice = input.nextInt();
        for (i = 0; i < 10; i++) {
        for (i = studentChoice + 1; i < studentNamesArray.length; i++) {
          studentNamesArray[i - 1] = studentNamesArray[i];
        }
        nameArrayCount = nameArrayCount - 1;
        studentNamesArray[studentNamesArray.length - 1] = null;
        for (i = studentChoice + 1; i < 9; i++) {
          for (int y = 0; y < 3; y++) {
            studentMarksArray[i - 1][y] = studentMarksArray[i][y];
          }
        }
        markArrayCount = markArrayCount - 1;
        for (int y = 0; y < 3; y++) {
          studentMarksArray[9][y] = 0;
        }
      }
    }
    if (!studentFound) {
      System.out.println("There are no students stored");
    }
  }

Answer 1

仅使用 for 循环打印学生姓名。并在打印完所有学生后阅读studentChoice 一次。否则在打印studentNamesArray[0]后等待输入

System.out.println("Which student would you like to delete?");
for (int i = 0; i < 10; i++) {
  if (studentNamesArray[i] != null) {
    studentFound = true;
    System.out.println(i + ": " + studentNamesArray[i]);
  }
}
int studentChoice = input.nextInt();

Answer 2

确保数组的内容不为空，否则不会打印出来

Answer 3

我在这里看到的唯一原因，其他元素应该是null。您可以按如下方式确定

 for (int i = 0; i < 10; i++) {
   if (studentNamesArray[i] != null) {
      studentFound = true;
      System.out.println("Which student would you like to delete?");
      System.out.println(i + ": " + studentNamesArray[i]);
      int studentChoice = input.nextInt();// you need to check this 
     }else{
      System.out.println(i + ": " + studentNamesArray[i]);
     }
   }

但是可能还有别的原因。如果input.nextInt() 取自Scanner，您的程序将在那里等待用户输入。然后您必须提供该输入才能继续。确保这些事情。