【发布时间】:2011-05-05 08:28:01
【问题描述】:
我有一个页面允许用户上传图片,该图片由 {{MEDIA_ROOT}}/image/image1.jpg 中的 models.py 文件存储 我想通过另一个网页上的 html 图像标签显示此图像
我的html代码sn-p是<img border="2" src="{{ MEDIA_URL }}/images/{{ghar.image}}" alt="venture picture here"/>
这里 ghar 是具有图像细节的对象
谁能帮我做同样的事情
我使用 Django 作为框架,使用 sqlite3 作为数据库
更新:
这是我的 models.py 函数
from django.db import models
class GharData(models.Model):
place = models.CharField(max_length=40)
typeOfProperty = models.CharField(max_length=30)
typeOfPlace = models.CharField(max_length=20)
price = models.IntegerField()
ownerName = models.CharField(max_length=80)
ownerEmail = models.EmailField(blank=True, null=True)
address = models.CharField(max_length=200)
nameOfVenture = models.CharField(max_length=100)
city = models.CharField(max_length=60)
size = models.CharField(max_length=60)
designedBy = models.CharField(max_length=50,blank=True,null=True)
description = models.CharField(max_length=500,blank=True,null=True)
ownerPhone = models.CharField(max_length=20)
def __unicode__(self):
return self.ownerName
class ImageData(models.Model):
property = models.ForeignKey(GharData, related_name='images')
image = models.ImageField(upload_to='image/',blank=True,null=True)
video = models.FileField(upload_to='video/',blank=True,null=True)
def __unicode__(self):
return self.property.ownerName
这是 urls.py
from django.conf.urls.defaults import patterns, include, url
import settings
# Uncomment the next two lines to enable the admin:
from django.contrib import admin
admin.autodiscover()
urlpatterns = patterns('',
url(r'^$', 'gharnivas.views.index'),
url(r'^search/$', 'gharnivas.views.search'),
url(r'^venture/(?P<ghar_id>\d+)/$', 'gharnivas.views.venture'),
url(r'^media/(?P<path>.*)$','django.views.static.serve',{'document_root': settings.MEDIA_ROOT}),
url(r'^admin/', include(admin.site.urls)),
)
提前非常感谢
【问题讨论】:
标签: django django-templates django-media