JSON/Django http 请求

Question

我编写了一些 django 代码，允许我请求一些数据并将其返回为 JSON 格式。

我请求：http http://127.0.0.0.8000/api/club

[
    {
        "name": "Liverpool FC",
        "abv": "LFC",
        "stadium": "Anfield",
        "manager": "Jurgen Klopp",
        "trophies": "50"
    },
    {
        "name": "Manchester City",
        "abv": "MC",
        "stadium": "Etihad",
        "manager": "Manuel Pellegrini",
        "trophies": "14"
    },
    {
        "name": "Manchester United",
        "abv": "MU",
        "stadium": "Old Trafford",
        "manager": "Louis Van Gaal",
        "trophies": "46"
    }
]

是否可以只请求“Liverpool FC”的数据以使请求只返回。我可以通过http http://127.0.0.0.8000/api/club/1/ 做到这一点，但我更愿意输入像http http://127.0.0.0.8000/api/club/liverpool/ 这样的团队名称

{
    "name": "Liverpool FC",
    "abv": "LFC",
    "stadium": "Anfield",
    "manager": "Jurgen Klopp",
    "trophies": "50"
}

编辑：添加了两个 py 文件

views.py

    # Create your views here.
    class FishViewSet(viewsets.ModelViewSet):
        # this fetches all the rows of data in the Fish table
        queryset = Fish.objects.all()
        serializer_class = FishSerializer

    # Create your views here.
    class TeamViewSet(viewsets.ModelViewSet):
        # this fetches all the rows of data in the Fish table
        queryset = Team.objects.all()
        serializer_class = TeamSerializer

    # Create your views here.
    class ClubViewSet(viewsets.ModelViewSet):
        # this fetches all the rows of data in the Fish table
        queryset = Club.objects.all()
        serializer_class = ClubSerializer

def getClub(request, club_name):
    queryset = Club.objects.get(name=club_name)

models.py

class Fish(models.Model):
        name = models.CharField(max_length=255)
        created = models.DateTimeField('auto_now_add=True')
        active = models.BooleanField()

class Team(models.Model):
        starting = models.CharField(max_length=255)
        captain = models.CharField(max_length=255)
        value = models.CharField(max_length=255)
        fixtures = models.CharField(max_length=255)
        position = models.CharField(max_length=255)

class Club(models.Model):
        name = models.CharField(max_length=255)
        abv = models.CharField(max_length=255)
        stadium = models.CharField(max_length=255)
        manager = models.CharField(max_length=255)
        trophies = models.CharField(max_length=255)

urls.py

router = routers.DefaultRouter()
#makes sure that the API endpoints work
router.register(r'api/fishes', views.FishViewSet)
router.register(r'api/teams', views.TeamViewSet)
router.register(r'api/club', views.ClubViewSet)

admin.autodiscover()

urlpatterns = router.urls

url(r'^admin/', include(admin.site.urls)),
url(r'^', include(router.urls)),
url(r'^api-auth/', include('rest_framework.urls', namespace='rest_framework'))
url(r'^/api/club/(?P<club_name>[a-zA-Z]+)/$', ('getClub'))

Answer 1

我知道一个使用正则表达式的简单方法

在 url.py 中添加这个正则表达式

url(r'^/api/club/(?P<club_name>[a-zA-Z]+)/$', ....)

然后在视图中添加一个方法将像这样的 club_name 变量

from django.http import HttpResponse

def getclub(request, club_name):
    teaminfo = ModelName.objects.get(name=club_name) # something like that
    return HttpResponse(teaminfo)

club_name 变量将从正则表达式中获取字符串，您可以随意使用它。

这是一个简单的很好的参考

https://docs.djangoproject.com/en/1.9/intro/tutorial03/

Answer 2

问题是您在视图中使用了queryset = Team.objects.all()。从本质上讲，这意味着您将获得所有对象。

我有一个类似的程序，我像这样使用urls.py-

...
url(r'^teams/(?P<incoming_team>[^/]+)/$', ('team_stats')),
url(r'^teams/', ('team_stats_all')),

在视图中它看起来像：

def team_stats(request, incoming_team):
    queryset = Team.objects.get(name=incoming_team)

显然，您现有的视图将用于所有人。我还要注意你需要一些 Try/Except 处理，以防你有重复的团队，或者你请求的团队不存在。

（实际上我并没有像这样将它们拆分成单独的视图，但它可以让您了解逻辑流程）