Python poplib：将电子邮件结果的正文检索为 NONE答案

【问题标题】：Python poplib: retrieving body of the email result to NONEPython poplib：将电子邮件结果的正文检索为 NONE
【发布时间】：2017-07-13 00:57:21
【问题描述】：

我可以得到电子邮件的主题，但正文总是显示为 NONE。尝试遵循此link，但所有建议最终都相同。正文仍然打印为 NONE。

import poplib
from email import parser
pop_conn = poplib.POP3_SSL('pop.gmail.com')
pop_conn.user('my_email.com')
pop_conn.pass_('my_password')
#Get messages from server:
messages = [pop_conn.retr(i) for i in range(1, len(pop_conn.list()[1]) + 1)]
# Concat message pieces:
messages = ['\n'.join(map(bytes.decode, mssg[1])) for mssg in messages]
#Parse message intom an email object:
messages = [parser.Parser().parsestr(mssg) for mssg in messages]

for message in messages:
    print (message['subject'])
    print (message['body'])
    print (message.get_payload())
pop_conn.quit()

【问题讨论】：

标签： python python-3.x poplib

【解决方案1】：

import poplib
from email import parser
pop_conn = poplib.POP3_SSL('pop.gmail.com')
pop_conn.user('my_email.com')
pop_conn.pass_('my_password')
#Get messages from server:
messages = [pop_conn.retr(i) for i in range(1, len(pop_conn.list()[1]) + 1)]
# Concat message pieces:
messages = ['\n'.join(map(bytes.decode, mssg[1])) for mssg in messages]
#Parse message intom an email object:
messages = [parser.Parser().parsestr(mssg) for mssg in messages]

for message in messages:
    print (message['subject'])
    print (message['from'])
    for part in message.walk():
        if part.get_content_type():
            body = part.get_payload(decode=True)
            print(body)
pop_conn.quit()

这成功了。但是它打印一条直线。如果邮件正文很长，有人知道如何按行打印吗？

【讨论】：