SQL Server 2005查找列行##----##之间的所有字符

Question

我有一个表模板，其中包含以下列：

ID，[文本]

---

假设我在一个模板表中有两条记录，

1, '他的全名是##Full_Name##，他于##Date_of_Birth## 出生于##Place_of_Birth## 市'

2，'我是##First_Name##，我出生于##Date_of_Birth##'

---

我想连续查找##Full_Name##、##Date_of_Birth## 和##Place_of_Birth##。

在另一行可以有两个匹配结果，分别是 ##First_Name## 和 ##Date_of_Birth## 。

两条记录的输出是这样的：

1、Full_Name、Date_of_Birth、Place_of_Birth

2、First_Name、Date_of_Birth

---

谁能帮帮我？

Answer 1

这里是：

DECLARE @Text NVARCHAR(MAX)
SET @Text ='His full name is ##Full_Name##,he was born on ##Date_of_Birth## in city of ##Place_of_Birth##'

DECLARE @Delimiter VARCHAR(1000)
SET @Delimiter = '##';

WITH 
    numbers(number)
      AS ( SELECT   ROW_NUMBER() OVER ( ORDER BY o.object_id, o2.object_id ) Number
           FROM     sys.objects o
                    CROSS JOIN sys.objects o2
         ) ,
    counts ( began, number )
      AS ( SELECT   CHARINDEX(@Delimiter, @TExt, 0)
                  , 1
           UNION ALL
           SELECT   CHARINDEX(@Delimiter, @TExt, began + 1)
                  , number + 1
           FROM     counts
           WHERE    CHARINDEX(@Delimiter, @TExt, began + 1) > 0
         ) ,
    subs ( began, ends, number )
      AS ( SELECT   C.began + LEN(@delimiter)
                  , c2.began
                  , c.number
           FROM     counts C
                    INNER JOIN counts C2 ON c2.number = c.number + 1
           WHERE    C.number % 2 = 1
         )
SELECT  SUBSTRING(@TExt, began, ( ends - began )) Word
FROM    subs

Answer 2

你可以实现 CLR Regex 函数。

这里是一个例子：Regular Expressions Make Pattern Matching And Data Extraction Easier