【发布时间】:2016-05-05 03:26:25
【问题描述】:
我有一个带有表格的模板,并且我有一个查询中的所有对象。每个对象可以有或没有相关的对象。假设这一点,我需要做的是,为每个对象检查是否有相关对象。如果不在表格中,我有一个字段可以放置链接以创建相关对象,但如果有显示图标以查看此对象。
我可以使用“父”对象之一,但如果查询中有多个对象,我不知道该怎么做。
要检查的模型:
class Accident(models.Model):
employee = models.ForeignKey(Employee)
place = models.IntegerField(choices=ACCIDENT_PLACE, default=1)
detail = models.CharField(max_length=255)
clinic = models.ForeignKey(Clinic)
is_urgency = models.BooleanField(default=False)
created = models.DateTimeField(auto_now_add=True)
updated = models.DateTimeField(auto_now=True)
created_by = models.ForeignKey(User,
related_name='accidents_created_by',
editable=False,
blank=True,
null=True
)
modified_by = models.ForeignKey(User,
related_name='accidents_modified_by',
editable=False,
blank=True,
null=True
)
class Meta:
verbose_name = "accidente"
verbose_name_plural = "accidentes"
def __str__(self):
return str(self.id)
class AccidentCertificate(models.Model):
accident = models.ForeignKey(Accident)
diagnostic = models.CharField(max_length=150)
return_day = models.DateField()
notes = models.CharField(max_length=255)
medication = models.CharField(max_length=255)
doctor = models.ForeignKey(Doctor)
presented = models.BooleanField(default=False)
created = models.DateTimeField(auto_now_add=True)
updated = models.DateTimeField(auto_now=True)
created_by = models.ForeignKey(User,
related_name='acc_certificates_created_by',
editable=False,
blank=True,
null=True
)
modified_by = models.ForeignKey(User,
related_name='acc_certificates_modified_by',
editable=False,
blank=True,
null=True
)
class Meta:
verbose_name = "certificado de accidente"
verbose_name_plural = "certificados de accidente"
ordering = ["-id"]
def __str__(self):
return str(self.id)
这是我的观点(只检查一个我已经知道有 1 个相关对象的对象)
class EmployeeDetailView(LoginRequiredMixin, DetailView):
# Chequeamos que el usuario se encuentre logeado
login_url = reverse_lazy('users:login')
model = Employee
template_name = 'employees/detail.html'
pk_url_kwarg = 'employee_id'
def get_context_data(self, **kwargs):
context_object_name = 'employee'
context = super(EmployeeDetailView, self).get_context_data(**kwargs)
employee = context['employee']
context['cuil'] = employee.cuil[:2]+'-'+employee.cuil[2:10]+'-'+employee.cuil[-1:]
# Tomamos los accidentes correspondientes al empleado
# y los pasamos al contexto
employee_accidents = Accident.objects.filter(employee=employee)
context['accidents'] = employee_accidents
# Tomamos el certificado del accidente si existe
accident_certificate = AccidentCertificate.objects.get(accident=employee_accidents)
return context
在模板中
<table class="table table-striped">
<thead>
<tr>
<th>ID Acc.</th>
<th>Fecha</th>
<th>Cant. Días</th>
<th>Locación</th>
<th>Detalle</th>
<th>Clinica</th>
<th>Urgencia</th>
<th>Cargado por</th>
<th>Certificado</th>
<th>Segimiento</th>
</tr>
</thead>
<tbody>
{% for a in accidents %}
<tr>
<td>{{ a.id }}</td>
<td>{{ a.created|date }}</td>
<td>-</td>
<td>{{ a.get_place_display }}</td>
<td>{{ a.detail }}</td>
<td>{{ a.clinic }}</td>
<td>
{% if a.is_urgency %}
Si
{% else %}
No
{% endif %}
</td>
<td>{{ a.created_by }}</td>
<td><a href="{% url 'accidents:add_certificate' a.id %}">{% bootstrap_icon "search" %}</a></td>
<td>{% bootstrap_icon "search" %}</td>
</tr>
{% empty %}
<p class="text-center">
<strong>NO HAY REGISTROS</strong>
</p>
{% endfor %}
</tbody>
</table>
在 sintesis 中,我需要处理与员工相对应的每起事故,并为每起事故检查这是否有 AccidentCertificate,是否已将链接放入表中以查看证书,如果没有将链接放入创建证书。
【问题讨论】:
-
从您的模型看来,一次事故可能有多个事故证明?
标签: django html-table views django-class-based-views