Django REST框架url正则表达式模式不匹配

Question

我正在编写一个 RESTful API 作为 django 项目的应用程序。 我的应用程序中有两个端点（将 url 导入到主项目的 urls.py 中），它们的定义如下所示：

testrest/urls.py

​​>

from django.conf.urls import url

from . import views

urlpatterns = [
    url(r'prices/(?P<ticker>[X]{1}[A-Z0-9]{3}:[A-Z0-9]{1}[A-Z09.-]{1,4})/?P<resolution>([0-9]{0,3})/$', views.historyPrices, name='prices'),
    url(r'chart/?P<name>([a-zA-Z0-9_\.-]{8,12})/$s', views.chart, name='pchart'),
]

testrest/views.py

​​>

from rest_framework import status
from rest_framework.decorators import api_view
from rest_framework.response import Response



# Create your views here.
@api_view(['GET'])
def historyPrices(request, ticker, resolution=1):
    if request.method == 'GET':
        try:
            # do something
            return Response({'foo': 'foobar'})

        except Exception as e:
            print ('Error: {0}'.format(e))
            return Response(status = status.HTTP_500_INTERNAL_SERVER_ERROR)     
    else:
        return Response(status = status.HTTP_405_METHOD_NOT_ALLOWED)



@api_view(['GET', 'POST', 'PUT', 'DELETE'])
def chart(request, name=None):
    if request.method == 'GET':     
        if (name is not None):      
            try:
                # do something
            except Exception as e:
                print('Error:',e)
                return Response(status = status.HTTP_404_NOT_FOUND)         

            return Response({'foo': 'bar')
        else:
            return Response(status = status.HTTP_400_BAD_REQUEST)


    elif request.method == 'POST':
        data = request.data
        # print(data)

        try:
            # do something
            return Response(status = status.HTTP_201_CREATED)       

        except Exception as ex:
            print('Unhandled exception: {0}'.format(e))
            return Response(status = status.HTTP_500_INTERNAL_SERVER_ERROR)


    elif request.method == 'PUT':
        print('Called with PUT')
        return Response(status=status.HTTP_501_NOT_IMPLEMENTED)

    elif request.method == 'DELETE':
        print('Called with DELETE')
        return Response(status=status.HTTP_501_NOT_IMPLEMENTED)

    else:
        return Response(status=status.HTTP_400_BAD_REQUEST)

我希望能够使用以下 url 进行调用（如下所示，返回 404 not found 错误：

curl http://127.0.0.1:8000/testrest/prices/XNAS:GOOG      (404)
curl http://127.0.0.1:8000/testrest/prices/XNAS:GOOG/     (404)
curl http://127.0.0.1:8000/testrest/prices/XNAS:GOOG/3    (404)
curl http://127.0.0.1:8000/testrest/prices/XNAS:GOOG/3/   (404)

curl http://127.0.0.1:8000/testrest/prices?ticker=XNAS:GOOG      (404)
curl http://127.0.0.1:8000/testrest/prices/?ticker=XNAS:GOOG&resolution=3    (404)
curl http://127.0.0.1:8000/testrest/prices?ticker=XNAS:GOOG&resolution=3/   (404)

我现在尝试从服务器加载手动创建的图表 (xyz)：

curl http://127.0.0.1:8000/testrest/chart/xyz                 (404)
curl http://127.0.0.1:8000/testrest/chart/xyz/                (404)
curl http://127.0.0.1:8000/testrest/chart?name=xyz            (404)

然后我尝试在服务器上发布（创建）一个新图表：

curl -H "Content-Type: application/json" -X POST -d '{/* data */}' http://127.0.0.1:8000/testrest/chart     (404)

为什么模式不匹配？

Answer 1

您的urls 中有一些拼写错误。您缺少 regex named group <resolution> 和 <name> 的语法。以下将匹配上述所有 404 失败：

urlpatterns = [
    url(r'prices/?(?P<ticker>[X]{1}[A-Z0-9]{3}:[A-Z0-9]{1}[A-Z09.-]{1,4})?/?(?P<resolution>[0-9]{0,3})/?$', views.historyPrices, name='prices'),
    url(r'chart/?(?P<name>[a-zA-Z0-9_\.-]{3,12})?/?$', views.chart, name='pchart')
]

另外，我将pchart url 中<name> 的长度更改为3 到12 之间（不知道你想怎么样）。