如何在Django中返回多个响应[重复]答案

【问题标题】：How to return multiple response in Django [duplicate]如何在Django中返回多个响应[重复]
【发布时间】：2022-01-11 14:41:54
【问题描述】：

我试图在循环结束后返回相同的响应，但我找不到实现它的方法。

在这里，我尝试过的错误是在分配之前引用了局部变量“TaskId”

views.py：

def GetCurrentRunningActivity(UserID):

        cursor = connection.cursor()
        cursor.execute('EXEC [dbo].[sp_GetCurrentRunningActivity] @UserId=%s',(UserID,))
        result_set = cursor.fetchall()
        cursor_set = cursor.fetchall()
        for row in result_set:  
            
                TaskId=row[0]
                Number=row[1]
                Opened=row[2]
                Contacttype=row[3]
                Category1=row[4]
                State=row[5]
                Assignmentgroup=row[6]
                CountryLocation=row[7]
                Openedfor=row[8]
                Employeenumber=row[9]
                Shortdescription=row[10]
                Internaldescription=row[11]
                Additionalcomments=row[12]
                TaskName = row[1]
                print("Number", Number)
 
                return Response({ "TaskId": TaskId, "Number":Number,"Opened":Opened, "Contacttype":Contacttype,
         "Category1":Category1, "State":State, "Assignmentgroup":Assignmentgroup, "CountryLocation":CountryLocation,
         "Openedfor":Openedfor, "Employeenumber":Employeenumber , "Shortdescription":Shortdescription,
         "Internaldescription":Internaldescription, "Additionalcomments":Additionalcomments,"TaskName":TaskName},status=status.HTTP_200_OK)
     
       return Response({ "TaskId": TaskId, "Number":Number,"Opened":Opened, "Contacttype":Contacttype,
     "Category1":Category1, "State":State, "Assignmentgroup":Assignmentgroup, "CountryLocation":CountryLocation,
     "Openedfor":Openedfor, "Employeenumber":Employeenumber , "Shortdescription":Shortdescription,
     "Internaldescription":Internaldescription, "Additionalcomments":Additionalcomments,"TaskName":TaskName},status=status.HTTP_200_OK)

【问题讨论】：

标签： django django-rest-framework django-views

【解决方案1】：

这里的循环逻辑有问题：每次循环结束时，您都试图“返回”。相反，您应该将数据收集到一个列表中，然后像这样只返回一次响应：

def GetCurrentRunningActivity(UserID):
    cursor = connection.cursor()
    cursor.execute('EXEC [dbo].[sp_GetCurrentRunningActivity] @UserId=%s',(UserID,))
    result_set = cursor.fetchall()
    cursor_set = cursor.fetchall()
    data = []
    for row in result_set:
        TaskId=row[0]
        Number=row[1]
        Opened=row[2]
        Contacttype=row[3]
        Category1=row[4]
        State=row[5]
        Assignmentgroup=row[6]
        CountryLocation=row[7]
        Openedfor=row[8]
        Employeenumber=row[9]
        Shortdescription=row[10]
        Internaldescription=row[11]
        Additionalcomments=row[12]
        TaskName = row[1]
        print("Number", Number)
        data.append({"TaskId": TaskId, "Number":Number,"Opened":Opened,
            "Contacttype":Contacttype, "Category1":Category1, "State":State,
            "Assignmentgroup":Assignmentgroup, "CountryLocation":CountryLocation,
            "Openedfor":Openedfor, "Employeenumber":Employeenumber ,
            "Shortdescription":Shortdescription, 
            "Internaldescription":Internaldescription,
            "Additionalcomments":Additionalcomments,"TaskName":TaskName
        })
    return Response({"data": data}, status=status.HTTP_200_OK)

还有，请不要忘记关注 PEP8

【讨论】：