【发布时间】:2015-02-04 22:22:34
【问题描述】:
是否有更“Python/Django”的方式来通过通用外键查询/过滤对象?我正在尝试获取特定软件的所有 FullCitation 对象,其中 is_primary 为 True。
我知道我不能这样做,但我想做这样的事情:
ct_supported = ContentType.objects.get(app_label="supportedprogram", model="software")
primary_citations = FullCitation.objects.filter(content_type__name=ct_supported, object_id__in='', is_primary=True)
models.py
class FullCitation(models.Model)
# the software to which this citation belongs
# either a supported software program or a non-supported software program
limit = models.Q(app_label = 'myprograms', model = 'supportedprogram') | models.Q(app_label = 'myprograms', model = 'nonsupportedprogram')
content_type = models.ForeignKey(ContentType), limit_choices_to = limit, )
object_id = models.PositiveIntegerField()
content_object = generic.GenericForeignKey('content_type', 'object_id')
is_primary = models.BooleanField(help_text="Is this the Primary Citation for the software program?")
class NonSupportedProgram(models.Model):
title = models.CharField(max_length=256, blank = True)
full_citation = generic.GenericRelation('FullCitation')
class SupportedProgram(models.Model):
title = models.CharField(max_length=256, blank = True)
full_citation = generic.GenericRelation('FullCitation')
# and a bunch of other fields.....
views.py #我目前的尝试
primary_citations = []
sw_citations = sw.full_citations.all()
for x in sw_citations:
if x.is_primary:
primary_citations.append(x)
【问题讨论】:
-
快速修复:使用列表理解 [cit for cit in sw.full_citations.all() if cit.is_primary]
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谢谢你,@Alvaro!这绝对有帮助。只是想知道是否有一种方法可以过滤 FullCitation 对象本身,它会更像 Django ......如果没有,我肯定会使用列表推导!
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您也可以使用生成器理解,
(x for x in y)来延迟数据库查询,仅在必要时执行。
标签: python django generic-foreign-key