从 urls.py 获取路由时出错

Question

我正在测试应用程序。有必要测试处理到达地址'http://127.0.0.1:8000/api/v1/test/api_address/'的请求的方法。请告诉我，如通过reverse()给客户端的完整地址

class MyTestCase(APITestCase):

    def setUp(self):
        self.message = {
            'username': 'user_name',
            'password': 'user_password',
        }

    def test_get_token(self):
        response = self.client.post(reverse('api_address'), self.message)
        self.assertEqual(response.status_code, status.HTTP_201_CREATED)

urls.py 的代码：

users_router = DefaultRouter()
users_router.register(r'test', TestViewSet, 'test')
users_router.register(r'test/api_address', APIAddressRequestSet, 'api_address')

对于当前的实现，reverse（'map address'）不起作用，会报错：

django.urls.exceptions.NoReverseMatch: Reverse for 'api_address' not found. 'api_address' is not a valid view function or pattern name.

Answer 1

DefaultRouter 的 url 名称是自动生成的，请检查 the docs。

先设置base_name：

# urls.py    
users_router = DefaultRouter()
users_router.register(r'test', TestViewSet, base_name='test')
users_router.register(r'test/api_address', APIAddressRequestSet,
                      base_name='api_address')

现在您的网址可以通过 reverse('test-list') reverse('test-detail') 等进行反向访问。请查看文档中的表格以获取其他名称。

您更新的测试：

class MyTestCase(APITestCase):

    def setUp(self):
        self.message = {
            'username': 'user_name',
            'password': 'user_password',
        }

    def test_get_token(self):
        # note the appended `-list` to the url name
        response = self.client.post(reverse('api_address-list'), self.message)
        self.assertEqual(response.status_code, status.HTTP_201_CREATED)