【发布时间】:2017-04-06 09:48:17
【问题描述】:
`function SaveDetails() {
// var frmData = $('#frmSaveDetails').serializeObject();
var form = $("#frmSaveDetails");
var frmdata = SerializeObject("frmSaveDetails");`
$.ajax("/Home/SaveDetails", {
type: 'POST',
data: frmdata,
async: true,
success: function (result) {
if (!result.success) {
//What to write here?
}
}
},
error: function () {
//alert('An error occurred, please try again.');
}
});
}
如何返回 JSON 响应并在表单中向相应控件显示错误。我想要没有警报消息。请帮助..提前谢谢你
【问题讨论】:
标签: json ajax model-view-controller