Jmeter-如何将文件从一个 AWS S3 存储桶复制到另一个存储桶？

Question

我将 tar.zip 文件放在 AWS S3 位置的 newbucket 中。我有脚本可以剪切文件并将其放在另一个 S3 存储桶中。每次我需要将文件从本地上传到 newbucket 作为 JSSR 预处理器以从本地上传文件。我可以将 S3 中的文件从一个存储桶复制粘贴到另一个存储桶吗？

Answer 1

我认为“官方”的方式是一般使用AWS CLI和aws s3 sync command in particular：

aws s3 sync s3://DOC-EXAMPLE-BUCKET-SOURCE s3://DOC-EXAMPLE-BUCKET-TARGET

可以从 JSR223 Sampler 或 OS Process Sampler 启动该命令

如果您更喜欢以编程方式执行此操作 - 请查看 Copy an Object Using the AWS SDK for Java 文章，代码 sn-p 以防万一：

import com.amazonaws.AmazonServiceException;
import com.amazonaws.SdkClientException;
import com.amazonaws.auth.profile.ProfileCredentialsProvider;
import com.amazonaws.regions.Regions;
import com.amazonaws.services.s3.AmazonS3;
import com.amazonaws.services.s3.AmazonS3ClientBuilder;
import com.amazonaws.services.s3.model.CopyObjectRequest;

import java.io.IOException;

public class CopyObjectSingleOperation {

    public static void main(String[] args) throws IOException {
        Regions clientRegion = Regions.DEFAULT_REGION;
        String bucketName = "*** Bucket name ***";
        String sourceKey = "*** Source object key *** ";
        String destinationKey = "*** Destination object key ***";

        try {
            AmazonS3 s3Client = AmazonS3ClientBuilder.standard()
                    .withCredentials(new ProfileCredentialsProvider())
                    .withRegion(clientRegion)
                    .build();

            // Copy the object into a new object in the same bucket.
            CopyObjectRequest copyObjRequest = new CopyObjectRequest(bucketName, sourceKey, bucketName, destinationKey);
            s3Client.copyObject(copyObjRequest);
        } catch (AmazonServiceException e) {
            // The call was transmitted successfully, but Amazon S3 couldn't process 
            // it, so it returned an error response.
            e.printStackTrace();
        } catch (SdkClientException e) {
            // Amazon S3 couldn't be contacted for a response, or the client  
            // couldn't parse the response from Amazon S3.
            e.printStackTrace();
        }
    }
}