在 GROUP_CONCAT 中搜索过滤数据

Question

我希望能够搜索我的产品（搜索产品名称或产品“代码”），然后过滤这些结果。

我不知道在 Google 或 SO 中搜索什么，每次我收到 Search GROUP_CONCAT using LIKE 或 Php and MySQL GROUP_CONCAT with separator comma and search where concat by comma 出现时，但我似乎无法绕过 HAVING 而不会出现错误我的数据库。我不确定这是否可能，或者我是否还差得远。

我的桌子是这样的：

产品表

+------------+--------------+----------------+-------------------------+---------------+
| product_id | product_name | product_status | product_date_available  | product_type  |
+------------+--------------+----------------+-------------------------+---------------+
|          1 | Rug          |              1 | 2020-01-24              |             0 |
|          2 | Scraper      |              1 | 2020-03-15              |             0 |
|          3 | Shovel       |              0 | 2019-04-24              |             0 |
|          4 | Bucket       |              1 | 2030-01-01              |             0 |
|          5 | Dog          |              1 | 2018-04-27              |             0 |
|          6 | Digging      |              1 | 2020-01-01              |             1 |
+------------+--------------+----------------+-------------------------+---------------+

产品类别表

+------------+-------------+
| product_id | category_id |
+------------+-------------+
|          1 |          17 |
|          2 |          22 |
|          3 |          22 |
|          4 |          17 |
+------------+-------------+

产品标签表

+------------+--------+
| product_id | tag_id |
+------------+--------+
|          1 |     11 |
|          2 |      6 |
|          3 |      7 |
|          4 |      7 |
+------------+--------+

产品代码表

+---------+------------+------------+
| code_id | product_id | code_value |
+---------+------------+------------+
|       1 |          1 | 47012.000  |
|       2 |          1 | 47012.001  |
|       3 |          2 | 47013.000  |
|       4 |          3 | 47014.000  |
|       5 |          3 | 47014.001  |
|       6 |          3 | 47014.002  |
+---------+------------+------------+

产品变体值表

+-------+------------+----------+
| pv_id | product_id | value_id |
+-------+------------+----------+
|     1 |          1 |        7 |
|     2 |          1 |        6 |
|     3 |          1 |       10 |
|     4 |          2 |        7 |
|     5 |          3 |       10 |
|     6 |          3 |        7 |
|     7 |          3 |       12 |
|     8 |          2 |       14 |
+-------+------------+----------+

这是我尝试过但无法开始工作的方法：

搜索产品代码

SELECT p.product_id,
  (SELECT GROUP_CONCAT(DISTINCT code_value) FROM `me_product_variant_codes` WHERE `product_id` = p.product_id) AS codes,
  (SELECT GROUP_CONCAT(DISTINCT value_id) FROM `me_product_variant_values` WHERE `product_id` = p.product_id) AS variant_values,
  (SELECT GROUP_CONCAT(DISTINCT tag_id) FROM `me_product_tags` WHERE `product_id` = p.product_id) AS product_tags
    FROM me_product AS p
    WHERE (p.product_status = '1' AND p.product_date_available <= CONVERT_TZ(NOW(), 'SYSTEM', '+13:00') AND p.product_type = '0')
    AND ((LOWER(p.product_name) LIKE '%47012%')
    GROUP BY p.product_id
    HAVING codes LIKE '%47012%'
    AND HAVING variant_values IN(7, 10)
    AND HAVING product_tags IN(11)
    ORDER BY product_name DESC
    LIMIT 24

我很清楚我可能有很大的错误，但经过数周的研究，我似乎没有更接近找到如何使这项工作的答案。

所以我希望作为一个例子，如果我搜索47012，它将根据上面的示例数据返回以下内容。

+------------+----------------------+----------------+--------------+
| product_id |        codes         | variant_values | product_tags |
+------------+----------------------+----------------+--------------+
|          1 | 47012.000, 47012.001 | 7, 6           |           11 |
+------------+----------------------+----------------+--------------+

但我目前遇到此错误

#1064 - You have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near 'GROUP BY p.product_id
    HAVING codes LIKE '%47012%'
    AND HAVING variant_v' at line 8

即使尝试我的查询的简单版本以至少得到一些结果也会给我一个错误

简化查询

SELECT p.product_id,
  (SELECT GROUP_CONCAT(DISTINCT code_value) FROM `me_product_variant_codes` WHERE `code_product_id` = p.product_id) AS codes
    FROM me_product AS p
    WHERE (p.product_status = '1' AND p.product_date_available <= CONVERT_TZ(NOW(), 'SYSTEM', '+13:00') AND p.product_type = '0')
    AND ((LOWER(p.product_name) LIKE '%47012%')
    GROUP BY p.product_id
    HAVING codes LIKE '%47012%'
    ORDER BY p.product_name DESC
    LIMIT 24

给我这个错误

#1064 - You have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near 'GROUP BY p.product_id
    HAVING codes LIKE '%47012%'
    ORDER BY p.product_n' at line 6

我刚刚注意到的另一个问题是，如果它与 product_name 或 codes 值之一匹配，我不确定如何返回结果

Answer 1

您应该摆脱所有这些相关的子查询，而是使用连接子查询来计算各种 CSV 项：

SELECT
    p.product_id,
    COALESCE(vc.codes, 'NA') AS codes,
    COALESCE(vv.variant_values, 'NA') AS variant_values,
    COALESCE(pt.product_tags, 'NA') AS product_tags
FROM me_product AS p
LEFT JOIN
(
    SELECT product_id, GROUP_CONCAT(DISTINCT code_value) AS codes
    FROM me_product_variant_codes
    WHERE code_value LIKE '%47012%'
    GROUP BY product_id
) vc
    ON vc.product_id = p.product_id
LEFT JOIN
(
    SELECT product_id, GROUP_CONCAT(DISTINCT value_id) AS variant_values
    FROM me_product_variant_values
    GROUP BY product_id
    HAVING COUNT(CASE WHEN value_id = 7 THEN 1 END) > 0 AND
           COUNT(CASE WHEN value_id = 10 THEN 1 END) > 0
) vv
    ON vv.product_id = p.product_id
LEFT JOIN
(
    SELECT product_id, GROUP_CONCAT(DISTINCT tag_id) AS product_tags
    FROM me_product_tags
    GROUP BY product_id
    HAVING COUNT(CASE WHEN tag_id = 11 THEN 1 END) > 0
) pt
    ON pt.product_id = p.product_id
WHERE
    p.product_status = '1' AND
    p.product_date_available <= CONVERT_TZ(NOW(), 'SYSTEM', '+13:00') AND
    p.product_type = '0' AND
    LOWER(p.product_name) LIKE '%47012%';