【发布时间】：2016-09-12 06:58:39
【问题描述】：
当我尝试在分页页面上的两个日期之间进行搜索时，结果出现在第一页上，当按下下一个时没有显示
请找到代码并尝试提供帮助， 注意：我用谷歌搜索，但只是通过名称搜索找到分页
<script>
src="http://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<script>
$(document).ready(function() {
$("tr:odd").addClass("odd");
});
</script><style type="text/css">
.odd{
background-color:#ccc;
}
@charset "utf-8";
div.pagination {
padding: 3px;
margin: 3px;
}
div.pagination a {
padding: 2px 5px 2px 5px;
margin: 2px;
border: 1px solid #AAAADD;
text-decoration: none; /* no underline */
color: #000099;
}
div.pagination a:hover, div.pagination a:active {
border: 1px solid #000099;
color: #000;
}
div.pagination span.current {
padding: 2px 5px 2px 5px;
margin: 2px;
border: 1px solid #000099;
font-weight: bold;
background-color: #000099;
color: #FFF;
}
div.pagination span.disabled {
padding: 2px 5px 2px 5px;
margin: 2px;
border: 1px solid #EEE;
color: #DDD;
}
</style><head>
<meta charset="utf-8">
<title>Untitled Document</title>
</head>
<body>
<form action="topics1.php" method="post">
<input type="date" name="date"/>
<input type="date" name="date1"/>
<input type="submit" value="search"/>
</form>
<br/>
<?php
/*
date SQL isset
*/
$date1 = isset ($_POST['date']) ? $_POST['date'] : "";
$date2 = isset ($_POST['date1']) ? $_POST['date1'] : "";
/*
Place code to connect to your DB here.
*/
$connect=mysqli_connect('localhost','root','123456','liwa');
mysqli_set_charset($connect,'utf8mb4');
// include your code to connect to DB.
$tbl_name="sat"; //your table name
// How many adjacent pages should be shown on each side?
$adjacents = 3;
/*
First get total number of rows in data table.
If you have a WHERE clause in your query, make sure you mirror it here.
*/
$query = "SELECT COUNT(*) as num FROM $tbl_name ";
$total_pages = mysqli_fetch_array(mysqli_query($connect,$query));
$total_pages = $total_pages['num'];
/* Setup vars for query. */
$targetpage = "topics1.php"; //your file name (the name of this file)
$limit = 3; //how many items to show per page
$page =isset ($_GET['page']) ? $_GET['page'] : "";
if($page)
$start = ($page - 1) * $limit;//2-1*10 page 2 //first item to display on this page
else
$start = 0; //if no page var is given, set start to 0
/* Get data. */
$sql = "SELECT * FROM sat
WHERE date BETWEEN '$date1' AND '$date2'
LIMIT $start, $limit ";
$result = mysqli_query($connect,$sql);
/* Setup page vars for display. */
if ($page == 0) $page = 1; //if no page var is given, default to 1.
$prev = $page - 1; //previous page is page - 1
$next = $page + 1; //next page is page + 1
$lastpage = ceil($total_pages/$limit); //lastpage is = total pages / items per page, rounded up.
$lpm1 = $lastpage - 1; //last page minus 1
/*
Now we apply our rules and draw the pagination object.
We're actually saving the code to a variable in case we want to draw it more than once.
*/
$pagination = "";
if($lastpage > 1)
{
$pagination .= "<div class=\"pagination\">";
//previous button
if ($page > 1)
$pagination.= "<a href=\"$targetpage?page=$prev\"><< previous</a>";
else
$pagination.= "<span class=\"disabled\"><< previous</span>";
//pages
if ($lastpage < 7 + ($adjacents * 2)) //not enough pages to bother breaking it up
{
for ($counter = 1; $counter <= $lastpage; $counter++)
{
if ($counter == $page)
$pagination.= "<span class=\"current\">$counter</span>";
else
$pagination.= "<a href=\"$targetpage?page=$counter\">$counter</a>";
}
}
elseif($lastpage > 5 + ($adjacents * 2)) //enough pages to hide some
{
//close to beginning; only hide later pages
if($page < 1 + ($adjacents * 2))
{
for ($counter = 1; $counter < 4 + ($adjacents * 2); $counter++)
{
if ($counter == $page)
$pagination.= "<span class=\"current\">$counter</span>";
else
$pagination.= "<a href=\"$targetpage?page=$counter\">$counter</a>";
}
$pagination.= "...";
$pagination.= "<a href=\"$targetpage?page=$lpm1\">$lpm1</a>";
$pagination.= "<a href=\"$targetpage?page=$lastpage\">$lastpage</a>";
}
//in middle; hide some front and some back
elseif($lastpage - ($adjacents * 2) > $page && $page > ($adjacents * 2))
{
$pagination.= "<a href=\"$targetpage?page=1\">1</a>";
$pagination.= "<a href=\"$targetpage?page=2\">2</a>";
$pagination.= "...";
for ($counter = $page - $adjacents; $counter <= $page + $adjacents; $counter++)
{
if ($counter == $page)
$pagination.= "<span class=\"current\">$counter</span>";
else
$pagination.= "<a href=\"$targetpage?page=$counter\">$counter</a>";
}
$pagination.= "...";
$pagination.= "<a href=\"$targetpage?page=$lpm1\">$lpm1</a>";
$pagination.= "<a href=\"$targetpage?page=$lastpage\">$lastpage</a>";
}
//close to end; only hide early pages
else
{
$pagination.= "<a href=\"$targetpage?page=1\">1</a>";
$pagination.= "<a href=\"$targetpage?page=2\">2</a>";
$pagination.= "...";
for ($counter = $lastpage - (2 + ($adjacents * 2)); $counter <= $lastpage; $counter++)
{
if ($counter == $page)
$pagination.= "<span class=\"current\">$counter</span>";
else
$pagination.= "<a href=\"$targetpage?page=$counter\">$counter</a>";
}
}
}
//next button
if ($page < $counter - 1)
$pagination.= "<a href=\"$targetpage?page=$next\">next >></a>";
else
$pagination.= "<span class=\"disabled\">next >></span>";
$pagination.= "</div>\n";
}
//this is the loop
?>
<?php
echo "<table border='1' width='50%' cellpadding='0' cellspacing='0'>";
while ($row=mysqli_fetch_array($result,MYSQLI_ASSOC)){
echo"<tr>";
echo"<td>";
echo $row['Suggestions'];
echo"</td>";
echo"<td>";
echo $row['date'];
echo"</td>";
echo"</tr>";
}
echo "</table>";
?>
<?=$pagination?>
</body>
</html>【问题讨论】：
-
请大家帮忙
标签： php mysql date search pagination