如何只选择前 5 个结果，然后显示更多.. 选项？

Question

如何选择前 5 个结果，然后添加查看更多选项？

下面是当前代码：

  <?php

   $query="SELECT * FROM messages where u_id = '$uid' ORDER BY id DESC";
   $result=mysql_query($query);

   $num=mysql_numrows($result);

    mysql_close();

    echo "";

     $i=0;
     while ($i < $num) {

  $otheris=mysql_result($result,$i,"sender_full_name"); 
  $sysid=mysql_result($result,$i,"sender_id");
   $dob=mysql_result($result,$i,"dob");

    // If $dob is empty
   if (empty($dob)) {

   $dob = "No new messages - 
   <a  id=missingdob href=/test.php?id=$uid>
   <bold>check later</bold></a>";
   }

   echo "<br><div id=linkcontain>
   <a id=otherlink href=$mem/profile.php?id=$uid>
    $manitis</a>
         <br><div id=dobpres>$dob</div></div>";

   echo "";

    $i++;
      }

       ?>

Answer 1

您应该尝试第一次选择 6 行，如果您获得 6 条记录，则使用“显示更多选项”显示前 5 行

"SELECT * FROM messages where u_id = '$uid' ORDER BY id DESC LIMIT 0, 6";

对于以后的时间，你应该有这样的查询：

"SELECT * FROM messages where u_id = '$uid' ORDER BY id DESC LIMIT 6, 5";
"SELECT * FROM messages where u_id = '$uid' ORDER BY id DESC LIMIT 11, 5";
"SELECT * FROM messages where u_id = '$uid' ORDER BY id DESC LIMIT 16, 5";
...
...

如果您能够获取请求的记录数，则每次“显示更多选项”。

Answer 2

$query="SELECT * FROM messages where u_id = '$uid' ORDER BY id DESC LIMIT 5"; 

http://dev.mysql.com/doc/refman/5.5/en/select.html

如果存在第 6 个显示还有更多选项，您可以考虑 LIMIT 6 个显示最多 5 个...

Answer 3

window.onload = function(){

$(".box").hide();
$(".box").slice(0, 5).show(); // select the first ten
$("#load").click(function(e){ // click event for load more
    e.preventDefault();
    $("div:hidden").slice(0, -1).show(); // select next hidden divs and show them
    $("#load-more-div").html(' ');
});}