【问题标题】:Android - How to I implement a search functionality and return the results back in a ListView?Android - 如何实现搜索功能并将结果返回到 ListView?
【发布时间】:2015-07-05 17:57:13
【问题描述】:

我有一个 EditText,用户可以在其中从字符串数组(arr [] = “A”、“B”、“ C”)。我有一个 ListView,我希望在用户单击键盘上的“完成”按钮时显示结果?如何在我的代码中执行此操作?

这是一个截图:

这是我的代码?

package com.mobilecomp.add.ssproj1;

import android.support.v7.app.ActionBarActivity;
import android.os.Bundle;
import android.view.Menu;
import android.view.MenuItem;


public class MainActivity extends ActionBarActivity {

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);
    }


    @Override
    public boolean onCreateOptionsMenu(Menu menu) {
        // Inflate the menu; this adds items to the action bar if it is present.
        getMenuInflater().inflate(R.menu.menu_main, menu);
        return true;
    }

    @Override
    public boolean onOptionsItemSelected(MenuItem item) {
        // Handle action bar item clicks here. The action bar will
        // automatically handle clicks on the Home/Up button, so long
        // as you specify a parent activity in AndroidManifest.xml.
        int id = item.getItemId();

        //noinspection SimplifiableIfStatement
        if (id == R.id.action_settings) {
            return true;
        }

        return super.onOptionsItemSelected(item);
    }
}



package com.mobilecomp.add.ssproj1;

import android.support.v4.app.Fragment;
import android.os.Bundle;
import android.view.LayoutInflater;
import android.view.View;
import android.view.ViewGroup;


/**
 * A placeholder fragment containing a simple view.
 */
public class MainActivityFragment extends Fragment {

    public MainActivityFragment() {
    }

    @Override
    public View onCreateView(LayoutInflater inflater, ViewGroup container,
                             Bundle savedInstanceState) {
        return inflater.inflate(R.layout.fragment_main, container, false);
    }
}

activity_main.xml

<fragment xmlns:android="http://schemas.android.com/apk/res/android"
    xmlns:tools="http://schemas.android.com/tools" android:id="@+id/fragment"
    android:name="com.mobilecomp.add.ssproj1.MainActivityFragment"
    tools:layout="@layout/fragment_main" android:layout_width="match_parent"
    android:layout_height="match_parent" />

fragment_main.xml

<RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android"
    xmlns:tools="http://schemas.android.com/tools" android:layout_width="match_parent"
    android:layout_height="match_parent" android:paddingLeft="@dimen/activity_horizontal_margin"
    android:paddingRight="@dimen/activity_horizontal_margin"
    android:paddingTop="@dimen/activity_vertical_margin"
    android:paddingBottom="@dimen/activity_vertical_margin" tools:context=".MainActivityFragment">

    <EditText
        android:layout_width="match_parent"
        android:layout_height="wrap_content"
        android:id="@+id/inputText"
        android:layout_centerHorizontal="true"
        android:inputType="text" />

    <ListView
        android:layout_width="wrap_content"
        android:layout_height="wrap_content"
        android:id="@+id/searchResult"
        android:layout_below="@+id/inputText"
        android:layout_centerHorizontal="true" />

</RelativeLayout>

【问题讨论】:

标签: android listview search


【解决方案1】:

我认为最好的选择是使用TextWatcher

editText.addTextChangedListener(new TextWatcher() {
            @Override
            public void onTextChanged(CharSequence s, int start, int before, int count) {

                // TODO Auto-generated method stub
            }

            @Override
            public void beforeTextChanged(CharSequence s, int start, int count, int after) {

                // TODO Auto-generated method stub
            }

            @Override
            public void afterTextChanged(Editable s) {

                // TODO Auto-generated method stub
            }
        });

【讨论】:

    【解决方案2】:

    首先使用android:id=@+id/button 将一些Button 添加到您的fragment_main。然后在你的片段中:

    private ListView mListView;
    private EditText mEditText;
    private Button mButton;
    private ArrayList<String> mData = new ArrayList<>();
    
    
    @Override
    public View onCreateView(LayoutInflater inflater, ViewGroup container,
                             Bundle savedInstanceState) {
        View v = inflater.inflate(R.layout.fragment_main, container, false);
    
        mListView = (ListView) v.findViewById(R.id.searchResult);
        mEditText = (EditText) v.findViewById(R.id.inputText);
        mButton = (Button) v.findViewById(R.id.button);
        final ArrayAdapter<String> mAdapter = new ArrayAdapter<String>(getActivity().getApplicationContext(),android.R.layout.simple_dropdown_item_1line);
        mListView.setAdapter(mAdapter);
    
        //Some random data...
        mData.add("A");
        mData.add("B");
        mData.add("C");
    
        //Trigger, set listener on sth... button example
        mButton.setOnClickListener(new View.OnClickListener() {
            @Override
            public void onClick(View v) {
                final String fromEditText = mEditText.getText().toString().trim();
                for (String aaa : mData) {
                    if (aaa.contains(fromEditText)) {
                        mAdapter.add(aaa);
                    }
                }
            }
        });
        return v;
    }
    

    编辑:

    您可以这样做:

        mEditText.setOnEditorActionListener(new TextView.OnEditorActionListener() {
            @Override
            public boolean onEditorAction(TextView v, int actionId, KeyEvent event) {
                if (actionId == EditorInfo.IME_ACTION_DONE
                        || event.getAction() == KeyEvent.FLAG_EDITOR_ACTION) {
                    final String fromEditText = mEditText.getText().toString().trim();
                    for (String aaa : mData) {
                        if (aaa.contains(fromEditText)) {
                            mAdapter.add(aaa);
                        }
                    }
                }
                return true;
            }
        });
    

    【讨论】:

    • 感谢 N1to。我想知道是否可以在不创建额外按钮的情况下做到这一点?我只想让用户使用键盘点击“完成”
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