PHP数组搜索不起作用

Question

谁能帮助我解决为什么我的 array_search 在我编写的这个 PHP 脚本中不起作用。我已经搞砸了好几天，无法弄清楚这个问题。我已经尝试将array_search 移动到整个地方，循环内，循环外，我得到了相同的结果。我尝试搜索不同的数组值，尝试包含我自己的函数来搜索我在网上找到的数组。我知道这些值在数组中，因为我将数组打印到 .txt 文件中进行调试，现在我不知道接下来要查找什么。有任何想法吗？

   <?php 
//this variable tells us how many drupal nodes or 'paystub pages' we need to create
$nodeCount = 0;
$i = 0;
//needed for creating a drupal node
//for this code to work this script must be run from the root of the drupal installation
require_once './includes/bootstrap.inc';
drupal_bootstrap(DRUPAL_BOOTSTRAP_FULL);
if ($handle = opendir('/var/www/html/pay.*********group.com/upload')) 
{
    /* This is the correct way to loop over the directory. */
    while (false !== ($file = readdir($handle))) 
    {
       if ($file != "." && $file != "..") 
       {
            $nodeCount++;
            //We convert the pdf documents into text documents and move put them in the converted folder
            $command = "pdftotext /var/www/html/pay.*********group.com/upload/" . $file . " /var/www/html/pay.*********group.com/upload/converted/" . $file . ".txt";
            //Execute the command above
            $output = exec($command);

        }   
    }       
    closedir($handle);      
}
//subtract two because the folders "array" and "converted" are included because PHP does not differentiate
//between folders and files
$nodeCount = $nodeCount - 2; 
echo "<br />";
echo "<b> $nodeCount pdf files converted </b>";
echo "<br />";
//open the directory
if ($handle2 = opendir('/var/www/html/pay.*********group.com/upload/converted')) 
{

    //check to see if we have reached the last file of our directory, if not stay in loop
    while (false !== ($currentText = readdir($handle2))) 
    {
        //filter out files named . and ..
       if ($currentText != "." && $currentText != "..") 
       {
            //Create a file for array to be printed to
            $createArray = fopen("/var/www/html/pay.*********group.com/upload/arrays/" . $currentText, "w+") or die ("Cannot find file to create array, ID 2");


            //read the file we are on from the loop into the array 
            $currArray = file("/var/www/html/pay.*********group.com/upload/converted/" . $currentText) or die ("Cannot find file to create array, ID 1");


            $ArrSearch = array_search("EMPLOYEE NO. ", $currArray);

            echo "<br />";
            echo "<b> $ArrSearch index found </b>";
            echo "<br />";

            //array_trim($currArray[$i]);           
            //var_dump($currArray[$i]);

            //print array to .txt file for debugging purposes
            $out = print_r($currArray, true);
            fwrite($createArray, $out);
            fclose($createArray);
            $i++;   

        }           
    }
}
?>

编辑：我根据您的结论修复了代码，我也在这里更新了代码。使用上面的代码，这是我在尝试转换 6 个 pdf 文件时得到的输出。在每个索引旁边，我应该有一个来自每个搜索的数组索引

6 pdf files converted 

index found 

index found 

index found 

index found 

index found 

index found 

Answer 1

我认为你已经在你的论点中换了针和干草堆......

$ArrSearch = array_search("EMPLOYEE NO. ", $currArray);

根据要求，评论已回复

@meagar：不确定这是否是问题所在，或者他们是否已经筋疲力尽，并且在两天的挫折之后只是在尝试任何事情。

Answer 2

array_search(needle, haystack)

你是不是有点不对劲？ （在 haystack 中寻找 needle，而不是相反）。

Answer 3

$idx= array_search($needle, $haystack);

你需要在你的代码中交换 needle 和 haystack

Answer 4

我猜您正在搜索带有员工编号的行，例如“EMPLOYEE NO. 7”等。如果您使用array_search("EMPLOYEE NO. ", $currArray)，它会搜索与完全“EMPLOYEE NO.”匹配的行，因此您不会得到任何点击。

如果您想搜索以“EMPLOYEE NO.”开头的值，您必须遍历数组并使用strpos() 来查找匹配项。