django.core.exceptions.FieldError：无法将关键字“学生”解析为字段。选项有：exam、id、student、student_id、subject、test

Question

我正在建立一个在线课程，学生可以在登录帐户时查看他们的结果，我不知道如何从数据库中查询结果以便能够生成老师发布的结果为每个学生。请问views.py怎么写？

我做了一些事情，但出现了错误。这是我的代码：

class Result(models.Model):
    student = models.ForeignKey(Students, on_delete=models.CASCADE)
    test = models.FloatField(null=True, blank=True)
    exam = models.FloatField(null=True, blank= True)
    subject = models.CharField(max_length=3, choices=SUBJECT, null=True)

    class Meta:
        ordering = ["-student"]

    def get_total(self):
        return self.exam + self.test

    def __str__(self):
        return self.student.first_name


class Students(models.Model):
    first_name = models.CharField(max_length=15, default='top')
    last_name = models.CharField(max_length=15, default='top')
    phone_number = models.IntegerField(default=0)
    email = models.EmailField()
    class_choice = models.CharField(max_length=3, choices=CLASS)
    last_accessed = models.DateTimeField(null=True, blank=True)
    user = models.ForeignKey(User, on_delete=models.CASCADE, null=True, blank=True)

    class Meta:
        ordering = ["last_name"]

    def __str__(self):
        return self.last_name

    def get_absolute_url(self):
        return reverse('students-detail', kwargs={'pk': self.pk})

Answer 1

通常，我们喜欢this

class Result(models.Model):
   student = models.ForeignKey(Students, related_name='results')

class Student(models.Model):
   name = models.CharField(max_length=15, default='top')


s1 = Student.objects.get(id=1)
res = s1.results.all()