【发布时间】:2014-04-08 18:51:22
【问题描述】:
我有一个 django 模型,如下所示:
from django.db import models
from mptt.models import MPTTModel, TreeForeignKey
class deg_course_cat(models.Model):
degree_code = models.CharField(max_length=24)
specialization = models.CharField(max_length=48)
category_level1 = models.CharField(max_length=48)
category_level2 = models.CharField(max_length=96)
category_level3 = models.CharField(max_length=48)
min_credit = models.IntegerField()
max_credit = models.IntegerField()
primarystuff = models.CharField(max_length=24)
class deg_course_cat_mptt(MPTTModel):
name = models.CharField(max_length=100, unique=False)
min_credit = models.IntegerField(null=True)
max_credit = models.IntegerField(null=True)
parent = TreeForeignKey('self', null=True, blank=True, related_name='children')
class MPTTMeta:
order_insertion_by = ['name']
# Create your models here.
django 模型 deg_course_cat 表中的数据如下所示:
我想根据模型及其数据创建 mptt 结构,即类似于以下结构:
我该如何解决这个问题?由于我是 python 新手,如果我能提前实现这一点,那就太好了。
我尝试了一些类似以下的代码,但不确定它的正确性:
from studentapp.models import deg_course_cat, deg_course_cat_mptt
#degreeroot = deg_course_cat_mptt.objects.create(name="DegreeRoot")
for degrees in deg_course_cat.objects.values_list('degree_code', flat=True):
degreearray = set(deg_course_cat.objects.values_list('degree_code', flat=True))
for i in range(0,len(degreearray)):
degree(i) = deg_course_cat_mptt.objects.create(name= degreearray(i), parent=degreeroot)
for categories_l1 in deg_course_cat.objects.values_list('category_level1', flat=True):
category_level1 = set(deg_course_cat.objects.values_list('category_level1', flat=True))
for categories_l2 in deg_course_cat.objects.values_list('category_level2', flat=True):
category_level2 = set(deg_course_cat.objects.values_list('category_level2', flat=True))
for categories_l3 in deg_course_cat.objects.values_list('category_level3', flat=True):
category_level3 = set(deg_course_cat.objects.values_list('category_level3', flat=True))
【问题讨论】:
标签: python django django-models django-mptt