保存时将模型与另一个模型关联答案

【问题标题】：Associating a model with another model when saving it保存时将模型与另一个模型关联
【发布时间】：2018-06-19 21:19:38
【问题描述】：

我有以下代码。产品是这样的：有一个书单。每本书上都有一个表格。此表单保存帖子并使其与这本特定书籍相关。当您单击图书项目时，您会看到与该图书项目相关的所有帖子列表。到目前为止，书籍列表工作正常，保存帖子数据工作正常，当您单击列表时，它（DetailView）显示帖子列表（而不是书籍描述，通常是使用 DetailView 的方式）正常。不起作用的是将帖子保存为与保存帖子的表单相关的特定书籍。更简单地说，当您保存帖子时，该帖子应该与表单所在的书籍相关。

非常感谢您的帮助。谢谢！

views.py：

class BookList(ListView):
model = Book
template_name='books/books.html'

    class PostForm(ModelForm):
        class Meta:
            model = Post
            # Previously I tried, unsuccessfully, this among others:
            # books = Book.objects.filter(book)
            # posts = Post.objects.filter(the_book=books)
            # model = posts
            fields = ['post']  
            widgets = {
            'post': forms.Textarea()
            }

    def get_context_data(self, **kwargs):
        context = super(BookList, self).get_context_data(**kwargs)
        context['form'] = BookList.PostForm
        return context

    def post(self, request, *args, **kwargs):
        form  = BookList.PostForm(request.POST)
        if form.is_valid():
            form.save()
        return render(request, self.template_name, {'form': form })

class Posts(DetailView):
    model = Book
    template_name='books/post_create.html'
    slug_field = 'id'

    def get_context_data(self, **kwargs):
        context = super().get_context_data(**kwargs)
        book = self.object
        posts = Post.objects.filter(the_book=book)
        context['posts'] = posts
        return context

models.py：

class Book(models.Model):
    book = models.CharField(max_length=1000, blank=False, null=False, default="1")

    def __str__(self):
        return self.book

class Post(models.Model):
    post = models.CharField(max_length=1000, blank=False, null=False)
    the_book = models.ForeignKey('Book', on_delete=models.CASCADE, default="1")
    date = models.DateTimeField(auto_now_add=True)

    def __str__(self):
        return self.post

books.html：

<ul>
{% for book in object_list %}
<div class='ui card'>
<a class="content" href='{% url 'books:posts' book.id %}'>
  <div class="header">{{ book }}</div>
</a>

<div class="ui bottom attached button">

   <form class='ui form' action='' method='post'> {% csrf_token %}
      {{ form.as_p }} 
      <div class='postbutton'>
      <input class='ui button' type="submit" value="Done" />
      </div>
  </form>

</div>

</div>
{% empty %}
<h5>You don't have any books!</h5>
{% endfor %}

post_create.html（名字后面会改……）：

<ul>
{% for post in posts %}
<div class='ui card'>
<a class="content">
  <div class="header">{{ post }}</div>
</a>
</div>
{% empty %}
<h5>You don't have any posts!</h5>
{% endfor %}

【问题讨论】：

标签： django django-models django-views

【解决方案1】：

试试这个：在表单中添加 book_id 隐藏输入：

<form class='ui form' action='' method='post'> {% csrf_token %}
  {{ form.as_p }} 
  <input type="hidden" name="book_id" value="{{ book.id }}">
  <div class='postbutton'>
  <input class='ui button' type="submit" value="Done" />
  </div>

并在您的 BookList 视图中使用它：

def post(self, request, *args, **kwargs):
    form  = BookList.PostForm(request.POST)
    if form.is_valid():
        post = form.save(commit=False)
        post.the_book_id = request.POST['book_id']
        post.save() 
    return render(request, self.template_name, {'form': form })

【讨论】：