Microsoft.Azure.Graphs：如何将结果转换为类型？答案

【问题标题】：Microsoft.Azure.Graphs : how to cast the result to a type?Microsoft.Azure.Graphs：如何将结果转换为类型？
【发布时间】：2018-05-02 19:03:19
【问题描述】：

在tutorial-develop-graph-dotnet 学习本教程时，所有 Gremlin 查询示例都返回动态结果。

喜欢：

IDocumentQuery<dynamic> query = client.CreateGremlinQuery<dynamic>(graph, "g.V().hasLabel('person')");
dynamic result in await query.ExecuteNextAsync();

结果是这样的：

{"id":"thomas","label":"person","type":"vertex","properties":{"firstName":[{"id":"8fec3d0f-7290-4e80-9f38-9306de998579","value":"Thomas"}],"age":[{"id":"932879da-55c0-4dbc-b68c-fb3ef1e1827a","value":44}]}}

但是如何使用CreateGremlinQuery 和ExecuteNextAsync 来返回一个普通的类Person 呢？

public class Person
{
    public string Id { get; set; }

    public string FirstName { get; set; }

    public string LastName { get; set; }

    public int Age { get; set; }
}

【问题讨论】：

标签： .net azure facebook-graph-api gremlin

【解决方案1】：

我的解决方案是这样的：

1] 注释 person 类：

public class Person
{
    [JsonProperty("id")]
    public string Id { get; set; }

    [JsonProperty("firstName")]
    public string FirstName { get; set; }

    [JsonProperty("lastName")]
    public string LastName { get; set; }

    [JsonProperty("age")]
    public int Age { get; set; }
}

2] 将结果转换为 JObject 并循环属性：

IDocumentQuery<dynamic> query = client.CreateGremlinQuery<dynamic>(graph, "g.V().hasLabel('person')");
while (query.HasMoreResults)
{
    foreach (JObject item in await query.ExecuteNextAsync<dynamic>())
    {
        var properties = (JObject)item["properties"];

        var personAsJObject = new JObject();
        foreach (var property in properties)
        {
            if (property.Value is JArray valueArray)
            {
                personAsJObject.Add(property.Key, valueArray.First["value"]);
            }
        }

        var person = personAsJObject.ToObject<Person>(); // Real person here
    }
}

【讨论】：